MySql 获取日期时间晚于现在的第一行的案例语句

MySql Case statement to get first row where datetime is after now

我有一个查询,当前将当前约会突出显示为 "NOW",将所有后续约会突出显示为 "NEXT"。我无法调整它,但只显示一个约会是下一个约会。

这是我目前所拥有的...

SELECT 
    user_name,
    DATE(apt_start_datetime) AS apt_date, 
    TIME(apt_start_datetime) AS apt_start_time,  
    TIME(apt_end_datetime) AS apt_end_time,
    CASE 
        WHEN (NOW() BETWEEN apt_start_datetime AND apt_end_datetime) THEN 'NOW' 
        ELSE 
            CASE WHEN (NOW() < apt_start_datetime) THEN 'NEXT' ELSE NULL END 
        END AS now_next
FROM 
    users 
JOIN 
    apts ON DATE_FORMAT(CURDATE(), "%x%v") = DATE_FORMAT(apt_start_datetime, "%x%v")
WHERE 
    user_id = 123456
ORDER BY 
    apt_date, 
    apt_start_time

这 returns 类似于:

user_name     apt_date       apt_start_time      apt_end_time     now_next
--------------------------------------------------------------------------
user1         2015-11-20     10:45:00            10:55:00         null
user2         2015-11-20     10:55:00            11:55:00         NOW
user3         2015-11-20     11:55:00            12:15:00         NEXT
user4         2015-11-20     12:15:00            12:35:00         NEXT
user5         2015-11-20     12:35:00            12:55:00         NEXT

但我想要的是:

user_name     apt_date       apt_start_time      apt_end_time     now_next
--------------------------------------------------------------------------
user1         2015-11-20     10:45:00            10:55:00         null
user2         2015-11-20     10:55:00            11:55:00         NOW
user3         2015-11-20     11:55:00            12:15:00         NEXT
user4         2015-11-20     12:15:00            12:35:00         null
user5         2015-11-20     12:35:00            12:55:00         null

有什么想法吗?

问题导致 sql

的这一部分
CASE WHEN (NOW() < apt_start_datetime) THEN 'NEXT' ELSE NULL END

所有 apt_start_datetime 早于 NOW() 的行将具有 "NEXT".

您必须找到 first apt_start_datetime ,然后是 NOW() 并且此日期时间用于比较而不是 apt_start_datetime.

在伪 sql 中类似于

CASE WHEN (NOW() < (SELECT apt_start_datetime FROM tbl WHERE apt_start_datetime > NOW() ORDER BY DIFF(apt_start_datetime,NOW()) DESC  LIMIT 1)) THEN 'NEXT' ELSE NULL END

编辑:这是最简单的解决方案,但会很慢