python 独特的结果

Question

我有 2 个带有 ip-Addresses 的文件，我想查看文件 1 中的哪些地址不在文件 2 中。我只是无法让它工作，我做错了什么？我得到以下代码：

access = []   
with open("C:\users\joey\desktop\access.log",'r') as bestand:
    for line in bestand:
        try:
            splittedline = line.split('sftp-session')[1].split("[")[1].split("]")[0]
        except Exception:
            continue
        access.append(splittedline)


nodes = []
with open("C:\users\joey\desktop\exit_nodes.csv",'r') as bestand1:
    for line in bestand1:
        nodes.append(line)


setA = set(access)
setB = set(nodes)
listC = list(setB - setA)

print listC

输出：（只是一小部分）

59.231\n', '78.41.115.145\n', '62.210.76.96\n', '84.53.203.38\n', '185.82.216.119\n', '176.10.99.205\n', '107.150.53.178\n', '37.157.192.208\n', '91.238.60.100\n', '110.93.23.170\n', '162.247.72.213\n', '18.239.0.140\n', '84.115.35.248\n', '106.187.37.158\n', '213.61.149.125\n', '86.178.119.84\n', '50.76.159.218\n', '46.72.101.220\n', '78.46.51.124\n', '178.162.193.213\n', '207.201.223.196\n', '101.99.64.150\n', '5.199.142.93\n', '5.165.42.171\n', '185.17.144.138\n', '81.219.51.206\n', '65.181.113.136\n', '185.13.37.158\n', '104.232.3.33\n', '77.109.141.140\n', '77.170.1.2\n', '93.126.101.223\n', '188.246.75.178\n', '193.107.85.61\n', '188.138.1.229\n', '108.26.225.148\n', '108.61.212.102\n', '128.79.53.244\n', '81.89.0.195\n', '94.23.30.53\n', '104.237.156.214\n', '68.233.235.217\n', '188.166.49.82\n', '192.3.177.167\n', '173.208.196.215\n', '77.109.138.44\n', '106.187.45.156\n', '78.142.175.70\n', '71.230.253.68\n', '66.146.193.31\n', '90.231.152.159\n', '122.19.43.24\n', '79.98.107.90\n', '178.9.251.184\n', '176.108.160.253\n', '93.95.228.116\n', '106.185.29.93\n', '109.169.23.202\n', '94.242.57.26\n', '79.165.223.209\n', '192.241.199.208\n', '162.220.56.186\n', '212.71.238.203\n', '178.79.161.152\n', '78.21.6.161\n', '85.159.113.228\n', '37.139.3.171\n', '104.167.102.244\n', '62.49.92.150\n', '66.220.3.179\n', '185.61.148.183\n', '104.167.113.138\n', '66.85.131.72\n', '37.59.123.142\n', '121.54.175.50\n', '94.242.251.112\n', '185.13.38.185\n', '24.175.166.20\n', '54.65.198.84\n', '176.123.6.101\n', '176.10.99.202\n', '176.106.54.54\n

Answer 1

在将它们添加到列表之前，尝试为您阅读的每一行删除换行符。我认为您的第二个列表中的换行符干扰了比较。

>>> a = "one two three\n"
>>> a
'one two three\n'
>>> a.rstrip("\n")
'one two three'
>>> a
'one two three\n'

Answer 2

我认为你分割线的部分有问题：

splittedline = line.split('sftp-session')[1].split("[")[1].split("]")[0]

我尝试了一些示例输入 access.log:

1.1.1.2
1.1.1.3

和exit_nodes.csv:

1.1.1.1
1.1.1.2
1.1.1.3
1.1.1.4

并使用您的（修改后的）脚本（使用 .strip() 删除换行符）

access = []   
with open('access.log', 'r') as a:
    for line in a:
        access.append(line.strip())

nodes = []
with open('exit_nodes.csv', 'r') as b:
    for line in b:
        nodes.append(line.strip())

setA = set(access)
setB = set(nodes)
listC = list(setB - setA)

print listC

它会产生正确的输出，exit_nodes.csv 中但不在 access.log 中的所有内容：

>>> 
['1.1.1.4', '1.1.1.1']

Answer 3

我猜你的输入是 sftp-session[127.0.0.1] 您应该使用正则表达式来解析您的数据。

import re

access = []   
with open("C:\users\joey\desktop\access.log",'r') as bestand:
    for line in bestand:
        re_match = re.search('sftp-session\[\s*(\d+\.\d+\.\d+\.\d+)\s*\]', line)
        if re_match:
            access.append(re_match.group(1))
        else:
            continue

通过这种方式，您将确保在数组中获得 100% 正确的数据。正如晦涩难懂的人所提到的，您的问题可能是输出中的换行符 \n。

python 独特的结果

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