Post 请求未从 iOS 设备到达服务器
Post request not reaching server from iOS device
正在尝试向远程 PHP 文件发出简单的 post 请求。我没有收到服务器上的参数。我使用 Postman Btw 收到的。所以服务似乎还可以。此处似乎缺少 iOS 代码。
- (void) sendPostRequest {
NSError *error;
NSURLSessionConfiguration *configuration = [NSURLSessionConfiguration defaultSessionConfiguration];
NSURLSession *session = [NSURLSession sessionWithConfiguration:configuration delegate:self delegateQueue:nil];
NSURL *url = [NSURL URLWithString:baseURLPost];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url];
[request addValue:@"application/json" forHTTPHeaderField:@"Content-Type"];
[request addValue:@"application/json" forHTTPHeaderField:@"Accept"];
[request setHTTPMethod:@"POST"];
NSDictionary *mapData = [[NSDictionary alloc] initWithObjectsAndKeys:
@"JSON", @"responseType",
[UserManager sharedInstance].user.username, @"username",
self.textView.text, @"text",
nil];
NSData *postData = [NSJSONSerialization dataWithJSONObject:mapData options:0 error:&error];
allowLossyConversion:YES];
[request setHTTPBody:postData];
[[session dataTaskWithRequest:request completionHandler:^(NSData *data, NSURLResponse *response, NSError *error) {
if (error) {
NSLog(@"%@", [error.userInfo valueForKey:@"NSDebugDescription"]);
} else {
NSArray *jsonResponseArray = [NSJSONSerialization JSONObjectWithData:data options:NSJSONReadingAllowFragments error:&error];
NSLog(@"%@", jsonResponseArray);
}
}] resume];
}
我的 PHP 代码接收 post 请求。
<?php
header("Content-type:application/json");
$postText= $_POST['text'];
$username = $_POST['username'];
$itemType = $_POST['itemType'];
$responseType = $_POST['responseType'];
$pictureLink = $_POST['pictureLink'];
$timestamp = $_POST['timestamp'];
$tags = $_POST['tags'];
if($timestamp==null){
$timestamp = date('Y-m-d G:i:s');
}
$arr = array('username' => $username);
echo json_encode($arr);
?>
由此而来的jsonResponseArray
是username = "<null>";
使用
$handle = fopen('php://input','r');
$jsonInput = fgets($handle);
而不是$_POST
像这样:
<?php
header("Content-type:application/json");
$handle = fopen('php://input','r');
$jsonInput = fgets($handle);
$arr = json_decode($jsonInput, true);
$postText= $arr['text'];
$username = $arr['username'];
$itemType = $arr['itemType'];
$responseType = $arr['responseType'];
$pictureLink = $arr['pictureLink'];
$timestamp = $arr['timestamp'];
$tags = $arr['tags'];
if($timestamp==null){
$timestamp = date('Y-m-d G:i:s');
}
$arr = array('username' => $username);
echo json_encode($arr);
?>
您的回答不正确,但这段代码对我有用:
//Dict -> your dictionary, url -> the url for the action
NSData *data = [NSJSONSerialization dataWithJSONObject:dict
options:0
error:&error];
NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init] ;
[request setURL:url];
NSString *postLength=[NSString stringWithFormat:@"%lu",(unsigned long)[data length]];
[request setHTTPMethod:@"POST"];
[request setValue:postLength forHTTPHeaderField:@"Content-Length"];
[request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];
[request setTimeoutInterval:20.0];
[request setHTTPBody:data];
//....
//rest of the code
我终于 re-wrote 整个 iOS class Swift 并且东西又开始滚动了。 PHP 服务已经有一段时间了,过去对我来说效果很好。
正在尝试向远程 PHP 文件发出简单的 post 请求。我没有收到服务器上的参数。我使用 Postman Btw 收到的。所以服务似乎还可以。此处似乎缺少 iOS 代码。
- (void) sendPostRequest {
NSError *error;
NSURLSessionConfiguration *configuration = [NSURLSessionConfiguration defaultSessionConfiguration];
NSURLSession *session = [NSURLSession sessionWithConfiguration:configuration delegate:self delegateQueue:nil];
NSURL *url = [NSURL URLWithString:baseURLPost];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url];
[request addValue:@"application/json" forHTTPHeaderField:@"Content-Type"];
[request addValue:@"application/json" forHTTPHeaderField:@"Accept"];
[request setHTTPMethod:@"POST"];
NSDictionary *mapData = [[NSDictionary alloc] initWithObjectsAndKeys:
@"JSON", @"responseType",
[UserManager sharedInstance].user.username, @"username",
self.textView.text, @"text",
nil];
NSData *postData = [NSJSONSerialization dataWithJSONObject:mapData options:0 error:&error];
allowLossyConversion:YES];
[request setHTTPBody:postData];
[[session dataTaskWithRequest:request completionHandler:^(NSData *data, NSURLResponse *response, NSError *error) {
if (error) {
NSLog(@"%@", [error.userInfo valueForKey:@"NSDebugDescription"]);
} else {
NSArray *jsonResponseArray = [NSJSONSerialization JSONObjectWithData:data options:NSJSONReadingAllowFragments error:&error];
NSLog(@"%@", jsonResponseArray);
}
}] resume];
}
我的 PHP 代码接收 post 请求。
<?php
header("Content-type:application/json");
$postText= $_POST['text'];
$username = $_POST['username'];
$itemType = $_POST['itemType'];
$responseType = $_POST['responseType'];
$pictureLink = $_POST['pictureLink'];
$timestamp = $_POST['timestamp'];
$tags = $_POST['tags'];
if($timestamp==null){
$timestamp = date('Y-m-d G:i:s');
}
$arr = array('username' => $username);
echo json_encode($arr);
?>
由此而来的jsonResponseArray
是username = "<null>";
使用
$handle = fopen('php://input','r');
$jsonInput = fgets($handle);
而不是$_POST
像这样:
<?php
header("Content-type:application/json");
$handle = fopen('php://input','r');
$jsonInput = fgets($handle);
$arr = json_decode($jsonInput, true);
$postText= $arr['text'];
$username = $arr['username'];
$itemType = $arr['itemType'];
$responseType = $arr['responseType'];
$pictureLink = $arr['pictureLink'];
$timestamp = $arr['timestamp'];
$tags = $arr['tags'];
if($timestamp==null){
$timestamp = date('Y-m-d G:i:s');
}
$arr = array('username' => $username);
echo json_encode($arr);
?>
您的回答不正确,但这段代码对我有用:
//Dict -> your dictionary, url -> the url for the action
NSData *data = [NSJSONSerialization dataWithJSONObject:dict
options:0
error:&error];
NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init] ;
[request setURL:url];
NSString *postLength=[NSString stringWithFormat:@"%lu",(unsigned long)[data length]];
[request setHTTPMethod:@"POST"];
[request setValue:postLength forHTTPHeaderField:@"Content-Length"];
[request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];
[request setTimeoutInterval:20.0];
[request setHTTPBody:data];
//....
//rest of the code
我终于 re-wrote 整个 iOS class Swift 并且东西又开始滚动了。 PHP 服务已经有一段时间了,过去对我来说效果很好。