PHP preg_match 如何grep下划线之间的字符串

Question

我有这个字符串：

mctrn_25595_AdvandSurthree

并想解析它以将数字 25595 提取到一个变量中，基本上 25595_ 后面的任何内容都提取到另一个变量中。

$scriptBasename = $_SERVER['SCRIPT_FILENAME'];
$scriptBasename = basename($scriptBasename);
$cuttedName = preg_replace( '/^mctrn_/', '' , $scriptBasename );
$port= preg_match('/[0-9]+/','',$scriptBasename);
$serverName= preg_match('/_"(.*)/','',$cuttedName);

echo($scriptBasename."\r\n"); 
echo($port."\r\n"); 
echo($serverName."\r\n");

我的命令行结果：

php mctrn_25595_AdvandSurthree.php  <<< script filename!
PHP Notice:  Array to string conversion in /home/bent/Downloads/mctrn_25595_AdvandSurthree.php on line 8
Array
0
0

我目前是 PHP 新手，但还没有做到 "such simple stuff"。

Answer 1

如果您知道字符串将始终采用 mctrn_[一些整数]_[文本字符串] 的形式，那么您可以只使用 explode() and list():

$scriptBasename = $_SERVER['SCRIPT_FILENAME'];
$scriptBasename = basename($scriptBasename);
list($mctrn,$port,$serverName) = explode('_',$scriptBasename);
echo($scriptBasename."\r\n"); 
echo($port."\r\n"); 
echo($serverName."\r\n");

否则如果你还想使用preg_match()，那么你可以试试这个：

$scriptBasename = $_SERVER['SCRIPT_FILENAME'];
$scriptBasename = basename($scriptBasename);
preg_match('#\_(\d+)+\_(\w+)#',$scriptBasename,$matches);
if (count($matches) > 1) {
    $port = $matches[1];
    $serverName = $matches[2];
    echo($scriptBasename."\r\n"); 
    echo($port."\r\n"); 
    echo($serverName."\r\n");
}

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