IOS: 如何获取数组中的字典值

Question

我正在做一个项目，我有一个包含字典的数组在给定的形式中，我必须在 "size_key".

的基础上获得 "Size_val" 的值

array : (
        {
        "as_per_size" =         {
            lowercatname = abcd;
            sizes =             (
                                {
                    "size_key" = "UP_CHEST";
                    "size_name" = "UP_CHEST";
                    "size_val" = 4;
                    typecat = 1;
                },
                            {
                "size_key" = LENGTH;
                "size_name" = LENGTH;
                "size_val" = 1;
                typecat = 1;
            },
                            {
                "size_key" = DP;
                "size_name" = DP;
                "size_val" = 3;
                typecat = 1;
            },
                            {
                "size_key" = "YOKE_LENGTH";
                "size_name" = "YOKE_LENGTH";
                "size_val" = 2;
                typecat = 1;
            },
                            {
                "size_key" = KNEE;
                "size_name" = KNEE;
                "size_val" = 2;
                typecat = 2;
            },
                            {
                "size_key" = THIGH;
                "size_name" = THIGH;
                "size_val" = 1;
                typecat = 2;
            },
                            {
                "size_key" = CALF;
                "size_name" = CALF;
                "size_val" = 3;
                typecat = 2;
            }
        );
        uppercatname = CHOLI;
    };

我只想在"size_key"的基础上得到"Size_val"的值。我使用代码获取 uppercatname 的值。

upstring1 = [[[arrFilteredOrder objectAtIndex:0] objectForKey:@"as_per_size"] objectForKey:@"uppercatname"];
            TypeLabel.text = upstring1;

请给我一些如何获得这个值的解决方案

Answer 1

请试试我下面的编码

NSDictionary *dict = (NSDictionary *)[[[arrFilteredOrder objectAtIndex:0] objectForKey:@"as_per_size"] objectForKey:@"sizes"];

Answer 2

NSArray *arr = [[[[array objectAtIndex:0]objectForKey:@"as_per_size"]objectForKey:@"sizes"]copy];

for(int i=0;i<[arr count];i++)
{
   NSString *strSizekey = [NSString stringWithFormat:@"%@",[[arr objectAtIndex:i]objectForKey:@"size_key"]];
   NSString *strSizeValue = [NSString stringWithFormat:@"%@",[[arr objectAtIndex:i]objectForKey:@"size_val"]];
}

Answer 3

显然你的尺寸值也是一个数组，所以你必须先得到这个数组，然后循环遍历尺寸数组以获得尺寸字典，并从尺寸字典中获得正确的 size_val size_key你有。

所以对于第一个条目和你的尺寸键:

NSArray* sizes = [[[arrFilteredOrder[0] objectForKey:@"as_per_size"] objectForKey;@"sizes];

foreach(NSDictionary* sizeDict in sizes {
    NSString* sizeKey = sizeDict[@"size_key];
    if([sizeKey isEqualToString:<your size key>])
    {
            NSString* sizeVal = sizeDict[@"size_val"];
            // now do something with your value
            ...
    }
}

Answer 4

你可以这样获取：

NSString *sizeValue = nil;

NSArray *sizes = [arrFilteredOrder.firstObject valueForKeyPath:@"as_per_size.sizes"];
for (NSDictionary *size in sizes) {
    if ([size[@"size_key"] isEqualToString:sizeKey]) {
        sizeValue = [size[@"size_val"] description]; //converting to string
    }
}

IOS: 如何获取数组中的字典值

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