php mysql where 子句不读取变量

Question

我这里开始火了

mysql_query 无法识别我的变量 $d1 即使我尝试重命名它

这是代码..

html:

<form action ="manageVessel.php" method ="POST">
  <select onchange ="this.form.submit();" class ="form-control" name ="ViewPositionCertificates">
      <option>Choose a Position </option>                                                       
      <?php
      $ViewPCertificates = mysql_query("SELECT * FROM table_cmsjob") or die("error" . mysql_error());
      while ($rwViewPCertificates = mysql_fetch_array($ViewPCertificates)) {
          ?>
          <option value =" <?php echo $rwViewPCertificates['jobName']; ?> "> <?php echo $rwViewPCertificates['jobName']; ?></option>  
      <?php } ?>

       </select>   
</form>

php:

   <?php if (isset($_POST['ViewPositionCertificates'])) { ?>
      <table class = "table table-bordered">
          <tr class ="bg-primary">
              <td> List of Certificates </td>
          </tr>
          <?php
          $d1 = $_POST['ViewPositionCertificates'];
          echo $_POST['ViewPositionCertificates'];
          $ViewCertificatesFP = mysql_query("SELECT * FROM table_cmsjobassigning WHERE jobName =  '$d1' ") or die("error" . mysql_error());

          while ($rwViewCertificatesFP = mysql_fetch_array($ViewCertificatesFP)) {

              echo "<tr>";
              echo "<td>" . $rwViewCertificatesFP['Certificate'] . "</td>";
              echo "</tr>";
          }
          ?>

      </table>




  <?php } ?>

MYSQL WHERE 子句在我使用字符串时工作正常

    mysql_query("SELECT * FROM table_cmsjobassigning WHERE jobName =  'MASTER' ") or die("error" . mysql_error());

但是当我使用变量将 $_POST['ViewPositionCertificates'] 赋值给变量时 MYSQL WHERE 子句没有任何帮助？

Answer 1

<?php if (isset($_POST['ViewPositionCertificates'])) { ?>
    <table class = "table table-bordered">
        <tr class ="bg-primary">
            <td> List of Certificates </td>
        </tr>
        <?php
        $d1 = $_POST['ViewPositionCertificates'];
        echo $_POST['ViewPositionCertificates'];
        $ViewCertificatesFP = mysql_query("SELECT * FROM table_cmsjobassigning WHERE jobName =  '".$d1."' ") or die("error" . mysql_error());

        while ($rwViewCertificatesFP = mysql_fetch_array($ViewCertificatesFP)) {

            echo "<tr>";
            echo "<td>" . $rwViewCertificatesFP['Certificate'] . "</td>";
            echo "</tr>";
        }
        ?>
    </table>
<?php } ?>

更改 select 查询语法使用单引号。

Answer 2

尝试更改您的查询方法，这可能会有所帮助...

$ViewCertificatesFP = mysql_query("SELECT * FROM table_cmsjobassigning WHERE jobName =  '".$d1."' ") or die("error" . mysql_error());

Answer 3

试试这个：

mysql_query("SELECT * FROM table_cmsjobassigning WHERE jobName =  ".$_POST['ViewPositionCertificates'])

Answer 4

不能在单引号内写变量，如果写的话PHP会认为是字符串。所以您的查询将是
$ViewCertificatesFP = mysql_query("SELECT * FROM table_cmsjobassigning WHERE jobName = $d1 ") or die("error" . mysql_error());

如需更多帮助，请阅读PHP

中的变量插值

Answer 5

这样试试..

$ViewCertificatesFP = mysql_query("SELECT * FROM table_cmsjobassigning WHERE jobName =  '".mysql_real_escape_string(trim($d1))."' ") or die("error" . mysql_error());

或

$ViewCertificatesFP = mysql_query("SELECT * FROM table_cmsjobassigning WHERE jobName =  '".addslashes(trim($d1))."' ") or die("error" . mysql_error());

Answer 6

<option value ="<?php echo $rwViewPCertificates['jobName']; ?>"> <?php echo $rwViewPCertificates['jobName']; ?></option>   // remove xtra spaces from here......

从 value 属性中删除空格

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