Sequelize many-to-many 自引用

Question

我正在尝试从 sequelize 中获得关联 examples 之一，但它似乎没有正确设置连接 table。在示例中，我们有一个名为 Person 的模型，然后有一个 many-to-many self-reference 表示一个人的 children。代码：

var Sequelize = require('sequelize');
var sequelize = new Sequelize('postgres://root@localhost/database_bug');

var Person = sequelize.define('Person', {
  id: {
    type: Sequelize.INTEGER,
    primaryKey: true,
    autoIncrement: true
  },
  name: {
    type: Sequelize.STRING,
    allowNull: false
  }
});

Person.belongsToMany(Person, { as: 'Children', through: 'PersonChildren' });

Person.sequelize.sync({force:true}).then(function() {
  Person.build({ name: 'John Doe' }).save().then(function(father) {
    Person.build({ name: 'Jane Doe' }).save().then(function(daughter) {
      father.addChild(daughter);
    });
  });
});

但是当我在 postgres 中查看我的 tables 时，我觉得 auto-generated 连接 table.

中缺少一列

            List of relations
 Schema |      Name      |   Type   | Owner 
--------+----------------+----------+-------
 public | People         | table    | root
 public | People_id_seq  | sequence | root
 public | PersonChildren | table    | root

                                    Table "public.People"
  Column   |           Type           |                       Modifiers                       
-----------+--------------------------+-------------------------------------------------------
 id        | integer                  | not null default nextval('"People_id_seq"'::regclass)
 name      | character varying(255)   | not null
 createdAt | timestamp with time zone | not null
 updatedAt | timestamp with time zone | not null
Indexes:
    "People_pkey" PRIMARY KEY, btree (id)
Referenced by:
    TABLE ""PersonChildren"" CONSTRAINT "PersonChildren_PersonId_fkey" FOREIGN KEY ("PersonId") REFERENCES "People"(id)

          Table "public.PersonChildren"
  Column   |           Type           | Modifiers 
-----------+--------------------------+-----------
 createdAt | timestamp with time zone | not null
 updatedAt | timestamp with time zone | not null
 PersonId  | integer                  | not null
Indexes:
    "PersonChildren_pkey" PRIMARY KEY, btree ("PersonId")
Foreign-key constraints:
    "PersonChildren_PersonId_fkey" FOREIGN KEY ("PersonId") REFERENCES "People"(id)

PersonChildren 需要一个名为 ChildId 的专栏或类似的内容以 link 一个人到其 Child.

人数table：

database_bug=# SELECT * FROM "People";
 id |   name   |         createdAt          |         updatedAt          
----+----------+----------------------------+----------------------------
  1 | John Doe | 2015-02-06 09:36:44.975-08 | 2015-02-06 09:36:44.975-08
  2 | Jane Doe | 2015-02-06 09:36:44.985-08 | 2015-02-06 09:36:44.985-08

更奇怪的是，我 select 确保 daughter 作为 child 添加到 father:

database_bug=# SELECT * from "PersonChildren";
         createdAt          |         updatedAt          | PersonId 
----------------------------+----------------------------+----------
 2015-02-06 09:36:44.997-08 | 2015-02-06 09:36:44.997-08 |        2

但是 PersonId 是 2，而不是 1。father 应该添加 daughter，而不是相反。

有什么想法可以让这个协会发挥作用吗？

Answer 1

好的，看起来文档中的示例是错误的。公平地说，他们确实说必须使用 hasMany 但随后显示了一个使用 belongsToMany.

的示例

我将 belongsToMany 更改为 hasMany，看来我们可以开始了：

          Table "public.PersonChildren"
  Column   |           Type           | Modifiers 
-----------+--------------------------+-----------
 createdAt | timestamp with time zone | not null
 updatedAt | timestamp with time zone | not null
 PersonId  | integer                  | not null
 ChildId   | integer                  | not null

database_bug=# select * from "PersonChildren";
         createdAt          |         updatedAt          | PersonId | ChildId 
----------------------------+----------------------------+----------+---------
 2015-02-06 10:04:21.624-08 | 2015-02-06 10:04:21.624-08 |        1 |       2

现在我可以执行 father.getChildren() 并且承诺将 return 子列表。

Sequelize many-to-many 自引用

Sequelize many-to-many self reference

postgresql

sequelize.js