如何使用 dplyr 加入多个数据帧?
How to join multiple data frames using dplyr?
我要left_join
多个数据帧:
dfs <- list(
df1 = data.frame(a = 1:3, b = c("a", "b", "c")),
df2 = data.frame(c = 4:6, b = c("a", "c", "d")),
df3 = data.frame(d = 7:9, b = c("b", "c", "e"))
)
Reduce(left_join, dfs)
# a b c d
# 1 1 a 4 NA
# 2 2 b NA 7
# 3 3 c 5 8
之所以有效,是因为它们都具有相同的 b
列,但是 Reduce
不允许我指定可以传递给 left_join
的其他参数。是否有解决此类问题的方法?
dfs <- list(
df1 = data.frame(a = 1:3, b = c("a", "b", "c")),
df2 = data.frame(c = 4:6, d = c("a", "c", "d")),
df3 = data.frame(d = 7:9, b = c("b", "c", "e"))
)
更新
这种工作方式:Reduce(function(...) left_join(..., by = c("b" = "d")), dfs)
但是当 by
不止一个元素时,它会给出此错误:Error: cannot join on columns 'b' x 'd': index out of bounds
这对你有用吗?
jnd.tbl <- df1 %>%
left_join(df2, by='b') %>%
left_join(df3, by='d')
我知道已经太迟了....今天我被介绍到未回答的问题部分。抱歉打扰了。
使用left_join()
dfs <- list(
df1 = data.frame(b = c("a", "b", "c"), a = 1:3),
df2 = data.frame(d = c("a", "c", "d"), c = 4:6),
df3 = data.frame(b = c("b", "c", "e"), d = 7:9)
)
func <- function(...){
df1 = list(...)[[1]]
df2 = list(...)[[2]]
col1 = colnames(df1)[1]
col2 = colnames(df2)[1]
xxx = left_join(..., by = setNames(col2,col1))
return(xxx)
}
Reduce( func, dfs)
# b a c d
#1 a 1 4 NA
#2 b 2 NA 7
#3 c 3 5 8
使用merge()
:
func <- function(...){
df1 = list(...)[[1]]
df2 = list(...)[[2]]
col1 = colnames(df1)[1]
col2 = colnames(df2)[1]
xxx=merge(..., by.x = col1, by.y = col2, , all.x = T)
return(xxx)
}
Reduce( func, dfs)
# b a c d
#1 a 1 4 NA
#2 b 2 NA 7
#3 c 3 5 8
另一种解决方案:
library(purrr)
library(dplyr)
dfs = list(
df1 = data.frame(a = 1:3, b = c("a", "b", "c")),
df2 = data.frame(c = 4:6, b = c("a", "c", "d")),
df3 = data.frame(d = 7:9, b = c("b", "c", "e"))
)
purrr::reduce(dfs, dplyr::left_join, by = 'b')
我要left_join
多个数据帧:
dfs <- list(
df1 = data.frame(a = 1:3, b = c("a", "b", "c")),
df2 = data.frame(c = 4:6, b = c("a", "c", "d")),
df3 = data.frame(d = 7:9, b = c("b", "c", "e"))
)
Reduce(left_join, dfs)
# a b c d
# 1 1 a 4 NA
# 2 2 b NA 7
# 3 3 c 5 8
之所以有效,是因为它们都具有相同的 b
列,但是 Reduce
不允许我指定可以传递给 left_join
的其他参数。是否有解决此类问题的方法?
dfs <- list(
df1 = data.frame(a = 1:3, b = c("a", "b", "c")),
df2 = data.frame(c = 4:6, d = c("a", "c", "d")),
df3 = data.frame(d = 7:9, b = c("b", "c", "e"))
)
更新
这种工作方式:Reduce(function(...) left_join(..., by = c("b" = "d")), dfs)
但是当 by
不止一个元素时,它会给出此错误:Error: cannot join on columns 'b' x 'd': index out of bounds
这对你有用吗?
jnd.tbl <- df1 %>%
left_join(df2, by='b') %>%
left_join(df3, by='d')
我知道已经太迟了....今天我被介绍到未回答的问题部分。抱歉打扰了。
使用left_join()
dfs <- list(
df1 = data.frame(b = c("a", "b", "c"), a = 1:3),
df2 = data.frame(d = c("a", "c", "d"), c = 4:6),
df3 = data.frame(b = c("b", "c", "e"), d = 7:9)
)
func <- function(...){
df1 = list(...)[[1]]
df2 = list(...)[[2]]
col1 = colnames(df1)[1]
col2 = colnames(df2)[1]
xxx = left_join(..., by = setNames(col2,col1))
return(xxx)
}
Reduce( func, dfs)
# b a c d
#1 a 1 4 NA
#2 b 2 NA 7
#3 c 3 5 8
使用merge()
:
func <- function(...){
df1 = list(...)[[1]]
df2 = list(...)[[2]]
col1 = colnames(df1)[1]
col2 = colnames(df2)[1]
xxx=merge(..., by.x = col1, by.y = col2, , all.x = T)
return(xxx)
}
Reduce( func, dfs)
# b a c d
#1 a 1 4 NA
#2 b 2 NA 7
#3 c 3 5 8
另一种解决方案:
library(purrr)
library(dplyr)
dfs = list(
df1 = data.frame(a = 1:3, b = c("a", "b", "c")),
df2 = data.frame(c = 4:6, b = c("a", "c", "d")),
df3 = data.frame(d = 7:9, b = c("b", "c", "e"))
)
purrr::reduce(dfs, dplyr::left_join, by = 'b')