从 MVC POST 操作方法调用 Web API 并接收结果

Question

我正在尝试从 MVC POST 操作方法调用 Web API 并接收结果但不确定如何接收结果，例如：

    [HttpPost]
    public ActionResult Submit(Model m)
    {
        // Get the posted form values and add to list using model binding
        IList<string> MyList = new List<string> { m.Value1,
                m.Value2, m.Value3, m.Value4};

        return Redirect???? // Redirct to web APi POST

        // Assume this would be a GET?
        return Redirect("http://localhost:41174/api/values")
    }

我想把上面的MyList传到Web上Api进行处理，然后它会传一个结果(int)给原来的controller:

// POST api/values
    public int Post([FromBody]List<string> value)
    {
        // Process MyList

        // Return int back to original MVC conroller
    }

不知道如何进行，感谢任何帮助。

Answer 1

您的 Web API 控制器本身不应该做太多事情。在具有适当的关注点分离的应用程序中，您的处理应该在其他地方完成。例如：

这可能在您的域模型中。

public class StringUtilities
{
    //Just a representative method of one way of processing the strings
    public int CountSomeStrings(IEnumerable<string> strings)
    {
        return strings.Count();
    }
}

您网站的一部分API

// POST api/values
public int Post([FromBody]List<string> value)
{
    return StringUtilities.CountSomeStrings(value);
}

然后在您的 MVC 控制器中调用，无需调用 Web API。直接调用它调用的方法即可。

[HttpPost]
public ActionResult Submit(Model m)
{
    // Get the posted form values and add to list using model binding
    IList<string> MyList = new List<string> { m.Value1,
            m.Value2, m.Value3, m.Value4};

    int NumStrings = StringUtilities.CountSomeStrings(MyList);
    ViewBag["NumStrings"] = NumStrings;
    return View();
}

Answer 2

您不应该使用 POST、a redirect almost always uses GET 进行重定向，但无论如何您都不想重定向到 API：浏览器将如何处理响应？

您必须执行 POST from your MVC controller and return the data。

像这样：

[HttpPost]
public ActionResult Submit(Model m)
{
    // Get the posted form values and add to list using model binding
    IList<string> postData  = new List<string> { m.Value1, m.Value2, m.Value3, m.Value4 };

    using (var client = new HttpClient())
    {
        // Assuming the API is in the same web application. 
        string baseUrl = HttpContext.Current
                                    .Request
                                    .Url
                                    .GetComponents(UriComponents.SchemeAndServer, UriFormat.SafeUnescaped);
        client.BaseAddress = new Uri(baseUrl);
        int result = client.PostAsync("/api/values", 
                                      postData, 
                                      new JsonMediaTypeFormatter())
                            .Result
                            .Content
                            .ReadAsAsync<int>()
                            .Result;

        // add to viewmodel
        var model = new ViewModel
        {
            intValue = result
        };

        return View(model);
    }           
}

Answer 3

在 Controller 中使用它

public async Task<ActionResult> EmployeeRegister(CreateEmployee model)
{
    HttpClient client = new HttpClient();
    client.BaseAddress = new Uri("http://localhost:8082/");
    client.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("application/json"));
    client.DefaultRequestHeaders.Accept.Clear();

    HttpResponseMessage response = await client.PostAsJsonAsync("api/CreateEmployee/PostEmployee", model);

    if (response.IsSuccessStatusCode == true)
    {
        return View();
     }

    return View();
}

从 MVC POST 操作方法调用 Web API 并接收结果

Call to Web API from MVC POST action method and receive a result

asp.net-mvc

asp.net-mvc-4

asp.net-web-api