点击警报时闯入内部

Question

我有一个按钮字段，在它被执行之前有一个警告。 "onclick" 警报代码包含一个文本。我无法在文本中刹车。我该如何解决？我找到了 [this question][1] 但我仍然无法解决它。问题是当我点击按钮时什么也没有发生。

echo "<tr><td><strong>
<form action='respondent.php' method='post'>
 <input type='hidden' name='rid' value='".$row['rid']."'>
 <input type='hidden' name='firstname' value='".$row['firstname']."'> 
<a href='respondent.php'><button>".$row['firstname']." ".$row['lastname']."</button></a>

 <input type='submit' name='submit' value='Select'>
 </form>
 </strong></td> 
 
 <td>".$row['email']."</td> 
 <td>".$row['pointsummary']."</td> 
 <td>".$row['datetime']."</td>
 
<td> 
<input type='button' action='deleterespondent.php' value='Delete' 
onclick="return confirm('Are you sure you \n want to delete?');">
</td>
</tr>";

Answer 1

这样使用\nconfirm('Are you sure you \n want to delete?'); \n 在字符串中使用，因此无需使用 'Are you sure you '\n' want to delete?'

演示：https://jsfiddle.net/b95yrrwu/

Answer 2

删除single quotes'周围\n

代码：

<input type='button' action='deleterespondent.php' value='Delete' 
onclick=\"return confirm('Are you sure you \n want to delete?');\">

输出

点击警报时闯入内部

Break inside on click alert

php

onclick