如何使用 contains() 函数检查字符串中是否存在预定义的子字符串以及 count() 匹配的字符串？

Question

我正在尝试检查字符串中是否存在预定义的子字符串，然后想要计算 () 与这些格式匹配的元素。

我的例子如下：

<!-- xslt code snippet; this is what I did, but I don't know
     how to count() them, I'm getting something like 111 as output :|
-->
<xsl:for-each select="automobile">
    <xsl:if test="contains(name_and_class, 'J.TK') or
        contains(name_and_class, 'P.LO') or contains(name_and_class, 'M.GA')">
        <xsl:value-of select="name_and_class"/>
 <!-- how can I count() them here-->
 
 <!-- xml code snippet -->
<automobile>
<name_and_class>Mercedes B.OO</name_and_class>
</automobile>
<automobile>
<name_and_class>Hummer P.LO</name_and_class>
</automobile>
<automobile>
<name_and_class>Audi J.TK</name_and_class>
</automobile>
<automobile>
<name_and_class>Ferrari M.GA</name_and_class>
</automobile>
<automobile>
<name_and_class>Mercedes F.BQ</name_and_class>
</automobile>

Answer 1

您可以使用谓词（[] 中的表达式）来过滤元素，例如假设我们有以下格式良好的 XML 作为输入：

<root>
    <automobile>
    <name_and_class>Mercedes B.OO</name_and_class>
    </automobile>
    <automobile>
    <name_and_class>Hummer P.LO</name_and_class>
    </automobile>
    <automobile>
    <name_and_class>Audi J.TK</name_and_class>
    </automobile>
    <automobile>
    <name_and_class>Ferrari M.GA</name_and_class>
    </automobile>
    <automobile>
    <name_and_class>Mercedes F.BQ</name_and_class>
    </automobile>
</root>

此模板将在不使用 xsl:for-each 的情况下输出符合条件的 name_and_class 个元素的计数：

<xsl:template match="/root">
    <xsl:value-of select="count(automobile[
        contains(name_and_class, 'J.TK') or
        contains(name_and_class, 'P.LO') or 
        contains(name_and_class, 'M.GA')
        ])"/>
</xsl:template>

xsltransform demo

输出：

如何使用 contains() 函数检查字符串中是否存在预定义的子字符串以及 count() 匹配的字符串？

How to use contains() function to check in strings the presence of predefined substrings and count() the strings that match?

xml

contains

count

xslt-1.0