无法通过查询 MySQL 数据库获得结果

Question

我在 MySQL 中使用一个数据库，其中有一个 table 说 ABC。

我想在数据库中查询给定的搜索关键字，并在 table 中显示输出。当我使用以下代码查询时，它工作正常：（玩过的游戏 1 是一个列名）

if($_POST['searchby'] == "Games Type"){
          $query_Recordset1 = "SELECT * FROM users_entity WHERE `Games Played 1' LIKE '%".$searchword."%'";

但是，当我尝试检查关键字是否出现在两列中时，玩过的游戏 1 或玩过的游戏 2，它不起作用。我为此使用了以下代码。

if($_POST['searchby'] == "Games Type"){
          $query_Recordset1 = "SELECT * FROM elgg_users_entity WHERE `Games Played 1` OR `Games Played 2` LIKE '%".$searchword."%'";

谁能指出我哪里做错了？？此外，当我运行使用上述代码的网页时，它会发出警告 "The MySQL server has gone away"

Answer 1

您的查询应该是这样的：

$query_Recordset1 = "SELECT * FROM elgg_users_entity WHERE `Games Played 1` LIKE '%".$searchword."%' OR `Games Played 2` LIKE '%".$searchword."%'";

Answer 2

if($_POST['searchby'] == "Games Type"){
          $query_Recordset1 = "SELECT * FROM elgg_users_entity WHERE `Games Played 1` LIKE '%".$searchword."%' OR `Games Played 2` LIKE '%".$searchword."%'";

Answer 3

错误

错误的 WHERE 条件。

所以最后的代码是

if($_POST['searchby'] == "Games Type"){
      $query_Recordset1 = "
      SELECT * 
      FROM elgg_users_entity 
      WHERE table_coumn1 
        LIKE '%$searchword%'  
      OR table_coumn2 
        LIKE '%$searchword%' ";

供您参考

Don't use spaces between table column names(Games Played 1). Add it with _separated word. (Games_Played_1).

Hence make it all small caps as best practices

无法通过查询 MySQL 数据库获得结果

Unable to get result from querying a MySQL database

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