如何编写这样复杂的查询？

Question

我有 table 份报告，其中包含：

rid     reparti
R00001  Ortopedi
R00002  Kardiologji
R00003  Gjinekologji

Table 名医生，其中包含：

did      demri    dmbiemri  titullli      rruga        qyteti    kp     shteti  mob         fix       email                 rid     paga
D00001   Shaban   Merovci   Dr Familjar   Mic Sokoli   Vushtrri  42000  Kosove  37744842203 28570369  shmerovci@gmail.com   R00001  1000

Table 约会：

tid     pid     did     rid     data_koha  konfirmimi
T00001  P00001  D00010  R00002  2015-12-20 08:30:00 1
T00002  P00009  D00004  R00003  2015-12-25 10:30:00 1

Table 住院（没有预约就不能住院）：

  hpid    pid     did     data_shtrimi  sid      terapia    diagnoza         tid
HP0001  P00009  D00004  2015-12-13    S00001   Barera     Hemorislapaskus  T00002
HP0002  P00006  D00002  2015-12-22    S00010   Kimoterapi Fragaria vesca   T00008
HP0003  P00001  D00002  2015-12-20    S00008   Barera     Depresion        T00001

Table 账单包含：

 fid     pid     hpid    cmimi_patvsh  tvsh  cmimi_metvsh data_fatures
    F00001  P00002  HP0005  85.00         0.18  100.30       2016-02-13
    F00002  P00009  HP0001  700.00        0.18  826.00       2016-12-10
    F00003  P00001  HP0003  120.00        0.18  141.60       2015-12-29

我的目的是为每个报告找到在其上工作的 NrDoktoreve 的医生 (did) 数量，该部分的 PagaMesatare 的平均 (paga)，NrHospitalizimeve 今年实现的住院人数，账单总和（值cmimi_patvsh，值 cmimi_metvsh) 今年实现。所有这些都应该在一个数据集列表中。

当然那些 table 包含更多数据我只是在这里放了一些例子。

Answer 1

查询并不太复杂，方法是识别连接列（table 组合在一起），编写连接，按 RID 对 table 进行分组（因为你想要每个 RID 的所有结果），最后选择字段。我没有可用于测试的 MySQL，但查询应如下所示：

select 
    rid,
    count(distinct did) NrDoktoreve, 
    avg(cmimi_metvsh) as PagaMesatare,
    count(distinct hpid) as NrHospitalizimeve,
    sum(cmimi_patvsh),
    sum(cmimi_metvsh)
        from reparts r 
        left join appointments a on r.rid = a.rid 
        left join hospitalization h on a.tod = h.tid 
        left join doctors d on r.rid = d.rid
        left join bills b on a.pid = b.pid
    group by rid
    order by rid;

如果您不喜欢table 编写 SQL，您可以考虑图形工具，如 DbSchema (http://www.dbschema.com/)（只是许多可用工具中的一个示例，但它确实有效MySQL).

没问题

Answer 2

这是我的问题的解决方案

select t1.rid,t1.reparti,t1.NrDoktoreve,t1.PagaMesatare,t2.NrHospitalizimeve,t3.VleraPaTvsh,t3.VleraMeTvsh from(
(select r.rid,r.reparti,count(d.did) as NrDoktoreve,avg(d.paga) as PagaMesatare from repartet r
left join doktoret d on r.rid=d.rid
group by r.rid order by r.rid ) as t1 left join 
(
select count(h.hpid) as NrHospitalizimeve ,r.rid
 from faturat f
inner join hospitalizimet h on f.hpid=h.hpid
inner join terminet t on h.tid=t.tid
inner join repartet r on t.rid=r.rid
where h.data_shtrimit between (curdate()-interval 1 year) and curdate() 
group by r.rid order by r.rid) as t2 on t1.rid=t2.rid left join
(select sum(f.cmimi_patvsh) as VleraPaTvsh,sum(f.cmimi_metvsh) as VleraMeTvsh,r.rid
from repartet r
left join terminet t on r.rid=t.rid
left join hospitalizimet h on t.tid=h.tid
left join faturat f on h.hpid=f.hpid
where data_fatures between (curdate()-interval 1 year) and curdate()
group by r.rid order by r.rid)as t3 on t2.rid=t3.rid)

如何编写这样复杂的查询？

How to write complicated query like this?

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