为什么双打不能从我的 String[] 数组中正确解析?

Why do doubles not correctly parse from my String[] array?

我正在尝试从一维字符串数组中解析双精度值。当我尝试这样做时,双打总是解析为 0.0,从来没有解析为正确的值。为什么会这样?

代码:

解析器方法:(忽略整数解析器,这个在给定整数时工作正常)

NumReturn numberParser(int cIndex) { // current index of array where num is
        NumReturn nri;
        NumReturn nrd;
        try {
        nri = new NumReturn(Integer.parseInt(Lexer.token[cIndex]), cIndex++, 'i');
        System.out.println(nri.value + " ");
        return nri;
        }
        catch (NumberFormatException intExcep) {

          }
        try {
        nrd = new NumReturn(Double.parseDouble((Lexer.token[cIndex])), cIndex++, 'd');
        System.out.println(nrd.dvalue + " ");
        return nrd;
        }
        catch (NumberFormatException doubExcep) {
            doubExcep.printStackTrace();
          }
        return null;


    }

NumReturn Class:

package jsmash;

public class NumReturn {
    int value;
    double dvalue;
    int pointerLocation;
    char type;
    NumReturn(int value, int pointerLocation, char type) {
        this.value = value;
        this.pointerLocation = pointerLocation;
        this.type = type;
    }
    NumReturn(double dvalue, int pointerLocation, char type) {
        this.dvalue = value;
        this.pointerLocation = pointerLocation;
        this.type = type;
    }
}

我试图解析的字符串数组:

static String[] token = new String[100];
token[0] = "129.4"; // I call my parser on this element of the array
token[1] = "+";
token[2] = "332.78"; // I call my parser on this element of the array

在我看来,这里的问题只是一个简单的错字。在第二个 NumReturn 构造函数(带有双参数的构造函数)中,您当前具有以下内容:

this.dvalue = value;

这会将 this.dvalue 赋给 this.value 的初始值,即 0。它完全忽略了构造函数参数。你真正想要的是:

this.dvalue = dvalue;
              ^