问题限制十进制长度

Issue limiting decimal length

我用来限制我所有 UITexField 中最多 1 个十进制数的代码:

func textField(textField: UITextField, shouldChangeCharactersInRange range: NSRange, replacementString string: String) -> Bool {
    let computationString = (textField.text! as NSString).stringByReplacingCharactersInRange(range, withString: string)


    let arrayOfSubStrings = computationString.componentsSeparatedByString(",")


    if (arrayOfSubStrings.count == 1 && computationString.characters.count > 2) {

        return false

    } else if arrayOfSubStrings.count == 2 {
        let stringPostDecimal = arrayOfSubStrings[1]

        return stringPostDecimal.characters.count <= 1
    }



    return true
}

但我只知道有两种类型的小数位:带点和带逗号。

例如,我的 iOS 模拟器使用点,我的 iPhone 使用逗号。 那么我该如何解决这个问题,同时停止这两个问题呢?

有一种方法componentsSeparatedByCharactersInSet可以考虑多个分隔符

let commaDotCharacterSet = NSCharacterSet(charactersInString: ",.")
let arrayOfSubStrings = computationString.componentsSeparatedByCharactersInSet(commaDotCharacterSet)

或者也包括当前语言环境的小数点分隔符

let localeDecimalSeparator = NSLocale.currentLocale().objectForKey(NSLocaleDecimalSeparator) as! String
let commaDotLocaleSeparatorCharacterSet = NSCharacterSet(charactersInString: ",." + localeDecimalSeparator)
let arrayOfSubStrings = computationString.componentsSeparatedByCharactersInSet(commaDotLocaleSeparatorCharacterSet)

试试这个。

func textField(textField: UITextField, shouldChangeCharactersInRange range: NSRange, replacementString string: String) -> Bool {
    let computationString = (textField.text! as NSString).stringByReplacingCharactersInRange(range, withString: string)

    let arrayOfSubStrings = computationString.computationString.componentsSeparatedByCharactersInSet(NSCharacterSet(charactersInString: ".,"))

    if (arrayOfSubStrings.count == 1 && computationString.characters.count > 2) {
        return false
    } else if arrayOfSubStrings.count == 2 {
        let stringPostDecimal = arrayOfSubStrings[1]
        return stringPostDecimal.characters.count <= 1
    }

    return true
}