比较集合中的元素并将其设置为该集合的最后一个元素

Question

如何实现：

比较集合中的元素（不知道索引，所以可以使用 contains/equals 来比较字符串值），检查是否存在然后必须向该字符串值添加一些字符（将被挑选从其他地方获取）然后将其添加回集合中成为最后一个元素。

示例场景：

xyz<Collection> contains these values:
"abc"
"hgj"
"jsh"
"yjk"

if (xyz.contains("jsh")){
then concat "jsh" + " " + randomOtherStuff
And put it back in the collection to be last element so when printed the order is 
"abc"
"hgj"
"yjk"
"jsh + " " + randomOtherStuff"
}

提前感谢大家的帮助:D

Answer 1

if (collection.contains("jsh")) {
  collection.remove("jsh"); // remove it, so it can be re-added to the end
  collection.add("jsh " + "asdfgdfgsdfhsjdfh"); // add the new string + some random stuff to the end of the list
}

比较集合中的元素并将其设置为该集合的最后一个元素

compare a element from a collection and set it to be last element of that collection

java

collections

arraylist

jakarta-ee