在没有第三个变量的情况下将 IEnumerable<List<string>> 转换为 IEnumerable<string>

Question

代码：

XElement elem = XElement.Load("http://localhost:54002/sample.xml");

IEnumerable<List<String>> elem1 = (from member in elem.Elements("member")
                            where (String.Equals(member.Attribute("class").Value, "prem", StringComparison.OrdinalIgnoreCase))
                            select member.Elements("customer").Select(f => f.Value.ToString()).ToList());

 IEnumerable<string> out; // required output format
 foreach (List<string> temp in elem1)
        {
           out  = temp;
        }

Sample.XML

<root>
<member class="gold">
        <customer>cust3</customer>
        <customer>cust5</customer>
        <customer>cust8</customer>
        <customer>cust1</customer>
</member>
<member class="prem">
        <customer>cust5</customer>
        <customer>cust1</customer>
        <customer>cust3</customer>
        <customer>cust2</customer>
</member>
<member class="silver">
        <customer>cust5</customer>
        <customer>cust8</customer>
        <customer>cust1</customer>
        <customer>cust4</customer>
</member>
</root>

我需要 return linq 以 IEnumerable 字符串格式输出而不使用 foreach 循环。简单来说，linq 查询本身应该 return 所需的输出。

Answer 1

你可以在LINQ fluent语法中使用SelectMany()直接returnList<string>:

IEnumerable<string> _out; // required output format
_out = elem.Elements("member")
           .Where(o => string.Equals(o.Attribute("class").Value, "prem", StringComparison.OrdinalIgnoreCase))
           .SelectMany(o => o.Elements("customer"))
           .Select(o => o.Value);

或者在查询语法中两次使用from子句与return相同，例如：

IEnumerable<string> _out; // required output format
_out = (from member in elem.Elements("member")
        where String.Equals(member.Attribute("class").Value, "prem", StringComparison.OrdinalIgnoreCase)
        from customer in member.Elements("customer")
        select customer.Value);

Dotnetfiddle Demo

在没有第三个变量的情况下将 IEnumerable<List<string>> 转换为 IEnumerable<string>

Convert IEnumerable<List<string>> to IEnumerable<string> without third variable

linq

linq-to-xml