Android 编辑文本输入过滤器
Android EditText InputFilter
如何使用过滤器一次删除两个字符?
我正在尝试对 EditText 应用一个简单的过滤器。
它必须按如下方式工作:
(要接收格式:1234 5678....)
===> 已编辑:第一部分效果很好。
1) 当 EditText 中有 4 位数字时,我正在输入第 5 位数字 -
首先必须出现一个space,然后是这个数字。
2)我需要一个相反的(在字符删除期间)-
space 必须删除第 5 个数字。
我的代码有什么问题?
editText.setFilters(new InputFilter[]{new DigitsKeyListener(Boolean.FALSE, Boolean.TRUE) {
@Override
public CharSequence filter(CharSequence source, int start, int end, Spanned dest, int dstart, int dend) {
// any chars except backspace
if (!source.equals("")) {
if (dest.length() == 4) {
// here I must add a space and then the source
// ===> EDITED:
return " " + source;
// return super.filter(" " + source, start, end + 1, dest, dstart, dend + 1);
} // backspace entered
} else {
if (dest.length() == 6) {
// here I must delete the 6-th character
// and the space before
return super.filter(source, 0, 0, dest, 5, 6);
}
}
return null;
}
}});
我建议你使用TextWatcher
来格式化你的EditText
输入,因为InputFilter
一般用于输入限制,决定什么可以输入而不是格式化文本。
您将使用此代码获得所需的输出:
String mTextValue;
Character mLastChar = '[=10=]'; // init with empty character
int mKeyDel;
myEditText.addTextChangedListener(new TextWatcher() {
@Override
public void onTextChanged(CharSequence s, int start, int before, int count) {
String eachBlock[] = myEditText.getText().toString().split(" ");
myEditText.setOnKeyListener(new View.OnKeyListener() {
@Override
public boolean onKey(View v, int keyCode, KeyEvent event) {
if (keyCode == KeyEvent.KEYCODE_DEL)
mKeyDel = 1;
return false;
}
});
if (mKeyDel == 0) {
if (((myEditText.getText().length() + 1) % 5) == 0) {
myEditText.setText(myEditText.getText() + " ");
myEditText.setSelection(myEditText.getText().length());
}
mTextValue = myEditText.getText().toString();
} else {
mTextValue = myEditText.getText().toString();
if (mLastChar.equals(' ')) {
mTextValue = mTextValue.substring(0, mTextValue.length() - 1);
myEditText.setText(mTextValue);
myEditText.setSelection(mTextValue.length());
}
mKeyDel = 0;
}
}
@Override
public void beforeTextChanged(CharSequence s, int start, int count, int after) {
if (s.length()>0) {// save the last char value
mLastChar = s.charAt(s.length() - 1);
} else {
mLastChar = '[=10=]';
}
}
@Override
public void afterTextChanged(Editable s) {}
});
请使用这个
public class CustomFormatWatcher implements TextWatcher {
private int size;
public CustomFormatWatcher(int size) {
this.size = size;
}
@Override
public void beforeTextChanged(CharSequence charSequence, int i, int i1, int i2) {
}
@Override
public void onTextChanged(CharSequence charSequence, int i, int i1, int i2) {
}
@Override
public void afterTextChanged(Editable editable) {
char hyphen = ' ';
char c = 0;
if (editable.length() > 0) {
c = editable.charAt(editable.length() - 1);
if (c == hyphen) {
editable.delete(editable.length() - 1, editable.length());
}
}
if (editable.length() > 0 && (editable.length() % size) == 0) {
c = editable.charAt(editable.length() - 1);
if (hyphen == c) {
editable.delete(editable.length() - 1, editable.length());
}
}
if (editable.length() > 0 && (editable.length() % size) == 0) {
c = editable.charAt(editable.length() - 1);
// Only if its a digit where there should be a space we insert a hyphen
if (Character.isDigit(c) && TextUtils.split(editable.toString(), String.valueOf(hyphen)).length <= 3) {
editable.insert(editable.length() - 1, String.valueOf(hyphen));
}
}
}
}
然后使用
myEditText.addTextChangedListener(new CustomFormatWatcher());
如何使用过滤器一次删除两个字符?
我正在尝试对 EditText 应用一个简单的过滤器。
它必须按如下方式工作:
(要接收格式:1234 5678....)
===> 已编辑:第一部分效果很好。
1) 当 EditText 中有 4 位数字时,我正在输入第 5 位数字 -
首先必须出现一个space,然后是这个数字。
2)我需要一个相反的(在字符删除期间)-
space 必须删除第 5 个数字。
我的代码有什么问题?
editText.setFilters(new InputFilter[]{new DigitsKeyListener(Boolean.FALSE, Boolean.TRUE) {
@Override
public CharSequence filter(CharSequence source, int start, int end, Spanned dest, int dstart, int dend) {
// any chars except backspace
if (!source.equals("")) {
if (dest.length() == 4) {
// here I must add a space and then the source
// ===> EDITED:
return " " + source;
// return super.filter(" " + source, start, end + 1, dest, dstart, dend + 1);
} // backspace entered
} else {
if (dest.length() == 6) {
// here I must delete the 6-th character
// and the space before
return super.filter(source, 0, 0, dest, 5, 6);
}
}
return null;
}
}});
我建议你使用TextWatcher
来格式化你的EditText
输入,因为InputFilter
一般用于输入限制,决定什么可以输入而不是格式化文本。
您将使用此代码获得所需的输出:
String mTextValue;
Character mLastChar = '[=10=]'; // init with empty character
int mKeyDel;
myEditText.addTextChangedListener(new TextWatcher() {
@Override
public void onTextChanged(CharSequence s, int start, int before, int count) {
String eachBlock[] = myEditText.getText().toString().split(" ");
myEditText.setOnKeyListener(new View.OnKeyListener() {
@Override
public boolean onKey(View v, int keyCode, KeyEvent event) {
if (keyCode == KeyEvent.KEYCODE_DEL)
mKeyDel = 1;
return false;
}
});
if (mKeyDel == 0) {
if (((myEditText.getText().length() + 1) % 5) == 0) {
myEditText.setText(myEditText.getText() + " ");
myEditText.setSelection(myEditText.getText().length());
}
mTextValue = myEditText.getText().toString();
} else {
mTextValue = myEditText.getText().toString();
if (mLastChar.equals(' ')) {
mTextValue = mTextValue.substring(0, mTextValue.length() - 1);
myEditText.setText(mTextValue);
myEditText.setSelection(mTextValue.length());
}
mKeyDel = 0;
}
}
@Override
public void beforeTextChanged(CharSequence s, int start, int count, int after) {
if (s.length()>0) {// save the last char value
mLastChar = s.charAt(s.length() - 1);
} else {
mLastChar = '[=10=]';
}
}
@Override
public void afterTextChanged(Editable s) {}
});
请使用这个
public class CustomFormatWatcher implements TextWatcher {
private int size;
public CustomFormatWatcher(int size) {
this.size = size;
}
@Override
public void beforeTextChanged(CharSequence charSequence, int i, int i1, int i2) {
}
@Override
public void onTextChanged(CharSequence charSequence, int i, int i1, int i2) {
}
@Override
public void afterTextChanged(Editable editable) {
char hyphen = ' ';
char c = 0;
if (editable.length() > 0) {
c = editable.charAt(editable.length() - 1);
if (c == hyphen) {
editable.delete(editable.length() - 1, editable.length());
}
}
if (editable.length() > 0 && (editable.length() % size) == 0) {
c = editable.charAt(editable.length() - 1);
if (hyphen == c) {
editable.delete(editable.length() - 1, editable.length());
}
}
if (editable.length() > 0 && (editable.length() % size) == 0) {
c = editable.charAt(editable.length() - 1);
// Only if its a digit where there should be a space we insert a hyphen
if (Character.isDigit(c) && TextUtils.split(editable.toString(), String.valueOf(hyphen)).length <= 3) {
editable.insert(editable.length() - 1, String.valueOf(hyphen));
}
}
}
}
然后使用
myEditText.addTextChangedListener(new CustomFormatWatcher());