在 PHP 中解析 JSONP

Question

我正在尝试解析 this JSONP file。过去我在解析 JSON 时运气不错，这是我第一次尝试 JSONP。我在该站点上的一些其他线程上读到，您可以使用 substr() 通过剥离 JavaScript 函数调用来获取数据。这是我的尝试：

<?php 
$json = file_get_contents("http://live.nhle.com/GameData/GCScoreboard/2016-01-18.jsonp");
$json = json_decode(substr($json, 15, 1));
echo var_dump($json);
$date = strtotime("now");
echo $date;
foreach ($json as $d) {
    $atCommon = $d['atcommon'];
    $idGame = $d['id'];
    $caNationalBroadcasts = $d['canationalbroadcasts'];
    $ata = $d['ata'];
    $r1 = $d['r1'];
    $atsog = $d['atsog'];
    $bs = $d['bs'];
    $htCommon = $d['htcommon'];
    $atn = $d['atn'];
    $hts = $d['hts'];
    $atc = $d['atc'];
    $htn = $d['htn'];
    $usNationalBroadcasts = $d['usnationalbroadcasts'];
    $gcl = $d['gcl'];
    $hta = $d['hta'];
    $ats = $d['ats'];
    $htc = $d['htc'];
    $htsog = $d['htsog'];
    $bsc = $d['bsc'];
    $gs = $d['gs'];
    $gcl1 = $d['gcl1'];

//  echo $htCommon;
//  echo $atCommon;
}
?>

到目前为止，我得到了这两个错误：
出于安全原因，警告 file_get_contents() 在第 2
行已被禁用
警告为第 7 行的 foreach() 提供的参数无效

另外，我知道 file_get_contents() 没有被禁用，因为我在下面的项目 *link 的多个其他地方使用了该功能。

这是我当前的输出（对于 JSONP 为空）：
空 1453102048 The Null and $date are hidden echo's beneath the stats link
问题基本上是这样的......我做错了什么？

Answer 1

如果您需要可变 url，最好将获取包装到一个函数中。

参见下面的示例

function get_JSONP($url){
    $ch = curl_init();
    curl_setopt($ch, CURLOPT_URL, $url);
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
    $output = curl_exec($ch);
    curl_close($ch);
    
    return $output;
    
}

function jsonp_decode($jsonp, $assoc = false) { // PHP 5.3 adds depth as third parameter to json_decode
    if($jsonp[0] !== '[' && $jsonp[0] !== '{') { 
        $jsonp = substr($jsonp, strpos($jsonp, '('));
    }
    $jsonp = trim($jsonp);      // remove trailing newlines
    $jsonp = trim($jsonp,'()'); // remove leading and trailing parenthesis
    
    return json_decode($jsonp, $assoc);
    
}

$url = "http://live.nhle.com/GameData/GCScoreboard/2016-01-18.jsonp";

$jsonp = get_JSONP($url);
$json = jsonp_decode($jsonp);

print_r($json);

将输出 $json 对象

stdClass Object
(
    [games] => Array
        (
            [0] => stdClass Object
                (
                    [usnationalbroadcasts] =>
                    [atcommon] => OILERS
                    [canationalbroadcasts] =>
                    [rl] =>
                    [ata] => EDM
                    [gcl] => 1
                    [ats] =>
                    [hta] => FLA
                    [htc] =>
                    [bs] => 7:30 PM
                    [htcommon] => PANTHERS
                    [id] => 2015020677
                    [atn] => EDMONTON
                    [hts] =>
                    [atc] =>
                    [gs] => 1
                    [bsc] =>
                    [htn] => FLORIDA
                    [gcll] => 1
                )

            [1] => stdClass Object
                (
                    [usnationalbroadcasts] => NBCSN
                    [atcommon] => PENGUINS
                    [canationalbroadcasts] => TVAS, SNE, SNO, SNP
                    [rl] =>

迭代内容

foreach($json->games as $game){
    print $game->canationalbroadcasts . PHP_EOL;
}

在 PHP 中解析 JSONP

Parsing JSONP in PHP

php

parsing

jsonp