sqlfiddle 上是否有示例表

Question

SqlFiddle 上是否有我可以查询的默认 table？

我想在简单的 table 上尝试基本的分析查询，但我不想设置模式和种子数据等。

通常我会做类似select * from all_objects

的事情

( http://sqlfiddle.com/ )

Answer 1

您可以在 SQLFiddle 应用程序中使用“View Sample Fiddle”。

Answer 2

汽车商店数据库：
SQL fiddle
图书馆数据库：
SQL fiddle
国家Table:
SQL fiddle

Answer 3

The following content is from "Auto Shop Database" from Stack Overflow Documentation (archived here); copyright 2017 by FlyingPiMonster, Prateek, forsvarir, Tot Zam, Florin Ghita, Abhilash R Vankayala, WesleyJohnson, Matt, Mureinik, Magisch, Bostjan, Mzzzzzz, Franck Dernoncourt, enrico.bacis, JavaHopper, rdans, bignose, and CL.; licensed under CC BY-SA 3.0. An archive of the full Stack Overflow Documentation content can be found at archive.org, in which this example is indexed by its topic ID: 280, as example: 1014.

汽车商店数据库

在以下示例中 - 汽车商店业务的数据库，我们有部门、员工、客户和客户汽车的列表。我们正在使用外键在各种 table 之间创建关系。

实例：SQL fiddle

table

之间的关系

每个部门可能有 0 名或更多员工
每个员工可以有 0 或 1 个经理
每个客户可能有 0 辆或更多辆汽车

部门

| Id | Name  |
|:---|:------|
| 1  | HR    |
| 2  | Sales |
| 3  | Tech  |

SQL 语句创建 table:

CREATE TABLE Departments (
    Id INT NOT NULL AUTO_INCREMENT,
    Name VARCHAR(25) NOT NULL,
    PRIMARY KEY(Id)
);

INSERT INTO Departments
    ([Id], [Name])
VALUES
    (1, 'HR'),
    (2, 'Sales'),
    (3, 'Tech')
;

员工

| Id | FName     | LName    | PhoneNumber | ManagerId | DepartmentId | Salary | HireDate   |
|:---|:----------|:---------|:------------|:----------|:-------------|:-------|:-----------|
| 1  | James     | Smith    | 1234567890  | NULL      | 1            | 1000   | 01-01-2002 |
| 2  | John      | Johnson  | 2468101214  | 1         | 1            | 400    | 23-03-2005 |
| 3  | Michael   | Williams | 1357911131  | 1         | 2            | 600    | 12-05-2009 |
| 4  | Johnathon | Smith    | 1212121212  | 2         | 1            | 500    | 24-07-2016 |

SQL 语句创建 table:

CREATE TABLE Employees (
    Id INT NOT NULL AUTO_INCREMENT,
    FName VARCHAR(35) NOT NULL,
    LName VARCHAR(35) NOT NULL,
    PhoneNumber VARCHAR(11),
    ManagerId INT,
    DepartmentId INT NOT NULL,
    Salary INT NOT NULL,
    HireDate DATETIME NOT NULL,
    PRIMARY KEY(Id),
    FOREIGN KEY (ManagerId) REFERENCES Employees(Id),
    FOREIGN KEY (DepartmentId) REFERENCES Departments(Id)
);

INSERT INTO Employees
    ([Id], [FName], [LName], [PhoneNumber], [ManagerId], [DepartmentId], [Salary], [HireDate])
VALUES
    (1, 'James', 'Smith', 1234567890, NULL, 1, 1000, '01-01-2002'),
    (2, 'John', 'Johnson', 2468101214, '1', 1, 400, '23-03-2005'),
    (3, 'Michael', 'Williams', 1357911131, '1', 2, 600, '12-05-2009'),
    (4, 'Johnathon', 'Smith', 1212121212, '2', 1, 500, '24-07-2016')
;

客户

| Id | FName   | LName  | Email                     | PhoneNumber | PreferredContact |
|:---|:--------|:-------|:--------------------------|:------------|:-----------------|
| 1  | William | Jones  | william.jones@example.com | 3347927472  | PHONE            |
| 2  | David   | Miller | dmiller@example.net       | 2137921892  | EMAIL            |
| 3  | Richard | Davis  | richard0123@example.com   | NULL        | EMAIL            |

SQL 语句创建 table:

CREATE TABLE Customers (
    Id INT NOT NULL AUTO_INCREMENT,
    FName VARCHAR(35) NOT NULL,
    LName VARCHAR(35) NOT NULL,
    Email varchar(100) NOT NULL,
    PhoneNumber VARCHAR(11),
    PreferredContact VARCHAR(5) NOT NULL,
    PRIMARY KEY(Id)
);

INSERT INTO Customers
    ([Id], [FName], [LName], [Email], [PhoneNumber], [PreferredContact])
VALUES
    (1, 'William', 'Jones', 'william.jones@example.com', '3347927472', 'PHONE'),
    (2, 'David', 'Miller', 'dmiller@example.net', '2137921892', 'EMAIL'),
    (3, 'Richard', 'Davis', 'richard0123@example.com', NULL, 'EMAIL')
;

汽车

| Id | CustomerId | EmployeeId | Model        | Status  | Total Cost |
|:---|:-----------|:-----------|:-------------|:--------|:-----------|
| 1  | 1          | 2          | Ford F-150   | READY   | 230        |
| 2  | 1          | 2          | Ford F-150   | READY   | 200        |
| 3  | 2          | 1          | Ford Mustang | WAITING | 100        |
| 4  | 3          | 3          | Toyota Prius | WORKING | 1254       |

SQL 语句创建 table:

CREATE TABLE Cars (
    Id INT NOT NULL AUTO_INCREMENT,
    CustomerId INT NOT NULL,
    EmployeeId INT NOT NULL,
    Model varchar(50) NOT NULL,
    Status varchar(25) NOT NULL,
    TotalCost INT NOT NULL,
    PRIMARY KEY(Id),
    FOREIGN KEY (CustomerId) REFERENCES Customers(Id),
    FOREIGN KEY (EmployeeId) REFERENCES Employees(Id)
);

INSERT INTO Cars
    ([Id], [CustomerId], [EmployeeId], [Model], [Status], [TotalCost])
VALUES
    ('1', '1', '2', 'Ford F-150', 'READY', '230'),
    ('2', '1', '2', 'Ford F-150', 'READY', '200'),
    ('3', '2', '1', 'Ford Mustang', 'WAITING', '100'),
    ('4', '3', '3', 'Toyota Prius', 'WORKING', '1254')
;

Answer 4

The following content is from "Library Database" from Stack Overflow Documentation (archived here); copyright 2017 by enrico.bacis, Bostjan, Shiva, WesleyJohnson, and Christian; licensed under CC BY-SA 3.0. An archive of the full Stack Overflow Documentation content can be found at archive.org, in which this example is indexed by its topic ID: 280, as example: 1014.

图书馆数据库

在这个图书馆的示例数据库中，我们有 Authors、Books 和 BooksAuthors tables.

实例：SQL fiddle

作者和书籍被称为基础tables，因为它们包含关系模型中实际实体的列定义和数据。 BooksAuthors 称为 关系 table，因为此 table 定义了 Books 之间的关系 和作者 table.

table

之间的关系

每位作者可以拥有 1 本书或多本书
每本书可以有一位或多位作者

作者

(view table)

| Id | Name                 | Country |
|:---|:---------------------|:--------|
| 1  | J.D. Salinger        | USA     |
| 2  | F. Scott. Fitzgerald | USA     |
| 3  | Jane Austen          | UK      |
| 4  | Scott Hanselman      | USA     |
| 5  | Jason N. Gaylord     | USA     |
| 6  | Pranav Rastogi       | India   |
| 7  | Todd Miranda         | USA     |
| 8  | Christian Wenz       | USA     |

SQL 创建 table:

CREATE TABLE Authors (
    Id INT NOT NULL AUTO_INCREMENT,
    Name VARCHAR(70) NOT NULL,
    Country VARCHAR(100) NOT NULL,
    PRIMARY KEY(Id)
);

INSERT INTO Authors
    (Name, Country)
VALUES
    ('J.D. Salinger', 'USA'),
    ('F. Scott. Fitzgerald', 'USA'),
    ('Jane Austen', 'UK'),
    ('Scott Hanselman', 'USA'),
    ('Jason N. Gaylord', 'USA'),
    ('Pranav Rastogi', 'India'),
    ('Todd Miranda', 'USA'),
    ('Christian Wenz', 'USA')
;

书籍

(view table)

|编号 |标题 | |:---|:------------------------------------| | 1 |麦田里的守望者 | | 2 |九个故事 | | 3 |弗兰妮和佐伊 | | 4 |了不起的盖茨比 | | 5 |夜晚的温柔| | 6 |傲慢与偏见 | | 7 | C# 专业 ASP.NET 4.5 和 VB |

SQL 创建 table:

CREATE TABLE Books (
    Id INT NOT NULL AUTO_INCREMENT,
    Title VARCHAR(50) NOT NULL,
    PRIMARY KEY(Id)
);

INSERT INTO Books
    (Id, Title)
VALUES
    (1, 'The Catcher in the Rye'),
    (2, 'Nine Stories'),
    (3, 'Franny and Zooey'),
    (4, 'The Great Gatsby'),
    (5, 'Tender id the Night'),
    (6, 'Pride and Prejudice'),
    (7, 'Professional ASP.NET 4.5 in C# and VB')
;

图书作者

(view table)

|书号 |作者编号 | |:--------|:--------| | 1 | 1 | | 2 | 1 | | 3 | 1 | | 4 | 2 | | 5 | 2 | | 6 | 3 | | 7 | 4 | | 7 | 5 | | 7 | 6 | | 7 | 7 | | 7 | 8 |

SQL 创建 table:

CREATE TABLE BooksAuthors (
    AuthorId INT NOT NULL,
    BookId  INT NOT NULL,
    FOREIGN KEY (AuthorId) REFERENCES Authors(Id),
    FOREIGN KEY (BookId) REFERENCES Books(Id)
);

INSERT INTO BooksAuthors
    (BookId, AuthorId)
VALUES
    (1, 1),
    (2, 1),
    (3, 1),
    (4, 2),
    (5, 2),
    (6, 3),
    (7, 4),
    (7, 5),
    (7, 6),
    (7, 7),
    (7, 8)
;

例子

查看所有作者（view live example）：

SELECT * FROM Authors;

查看所有书名（view live example）：

SELECT * FROM Books;

查看所有书籍及其作者（view live example）：

SELECT
  ba.AuthorId,
  a.Name AuthorName,
  ba.BookId,
  b.Title BookTitle
FROM BooksAuthors ba
  INNER JOIN Authors a ON a.id = ba.authorid
  INNER JOIN Books b ON b.id = ba.bookid
;

Answer 5

The following content is from "Countries Table" from Stack Overflow Documentation (archived here); copyright 2017 by enrico.bacis, Bostjan, and Shiva; licensed under CC BY-SA 3.0. An archive of the full Stack Overflow Documentation content can be found at archive.org, in which this example is indexed by its topic ID: 280, as example: 9933.

国家Table

在这个例子中，我们有一个国家 table。国家的 table 有很多用途，尤其是在涉及货币和汇率的金融应用程序中。

实例：SQL fiddle

某些市场数据软件应用程序，如彭博社和路透社，要求您为他们的 API 提供 2 或 3 个字符的国家/地区代码以及货币代码。因此，此示例 table 具有 2 个字符的 ISO 代码列和 3 个字符的 ISO3 代码列。

国家

(view table)

| Id | ISO | ISO3 | ISONumeric | CountryName   | Capital    | ContinentCode | CurrencyCode |
|:---|:----|:-----|:-----------|:--------------|:-----------|:--------------|:-------------|
| 1  | AU  | AUS  | 36         | Australia     | Canberra   | OC            | AUD          |
| 2  | DE  | DEU  | 276        | Germany       | Berlin     | EU            | EUR          |
| 2  | IN  | IND  | 356        | India         | New Delhi  | AS            | INR          |
| 3  | LA  | LAO  | 418        | Laos          | Vientiane  | AS            | LAK          |
| 4  | US  | USA  | 840        | United States | Washington | NA            | USD          |
| 5  | ZW  | ZWE  | 716        | Zimbabwe      | Harare     | AF            | ZWL          |

SQL 创建 table:

CREATE TABLE Countries (
    Id INT NOT NULL AUTO_INCREMENT,
    ISO VARCHAR(2) NOT NULL,
    ISO3 VARCHAR(3) NOT NULL,
    ISONumeric INT NOT NULL,
    CountryName VARCHAR(64) NOT NULL,
    Capital VARCHAR(64) NOT NULL,
    ContinentCode VARCHAR(2) NOT NULL,
    CurrencyCode VARCHAR(3) NOT NULL,
    PRIMARY KEY(Id)
)
;

INSERT INTO Countries
    (ISO, ISO3, ISONumeric, CountryName, Capital, ContinentCode, CurrencyCode)
VALUES
    ('AU', 'AUS', 36, 'Australia', 'Canberra', 'OC', 'AUD'),
    ('DE', 'DEU', 276, 'Germany', 'Berlin', 'EU', 'EUR'),
    ('IN', 'IND', 356, 'India', 'New Delhi', 'AS', 'INR'),
    ('LA', 'LAO', 418, 'Laos', 'Vientiane', 'AS', 'LAK'),
    ('US', 'USA', 840, 'United States', 'Washington', 'NA', 'USD'),
    ('ZW', 'ZWE', 716, 'Zimbabwe', 'Harare', 'AF', 'ZWL')
;

Answer 6

对于 MySQL 小提琴，请点击中的链接。

对于相同表的 Microsoft SQL Server 版本，请使用这些链接：

汽车商店数据库：
SQL fiddle
图书馆数据库：
SQL fiddle
国家Table:
SQL fiddle

sqlfiddle 上是否有示例表

Are there sample tables on sqlfiddle

sqlfiddle

table

部门

员工

客户

汽车

table

作者

书籍

图书作者

例子

国家