获取与正则表达式匹配的不完整单词

Question

我有一段文字，我需要找到以一个词开头的词，我需要得到与这个表达式匹配的完整词。

示例：我在如下文本中搜索 "abc"："Hi abc is abc123" 我需要得到一个数组：[0] = "abc" and [1] = "abc123" 因为两者都与我的表达式匹配 "abc".

我有这个代码：

$words = [];
    foreach($items as $i){
        $text = $l->getText();
        preg_match('*'."#".$q.'*', $text, $words[]);
    }

但我总是[0] = "abc" and [1] = "abc"。

我该怎么做？

Answer 1

//Regular expresson to find: 'abc', followed by any 
//characters, until a whitespace character
$re = "/(abc[^\s]*)/"; 

//String to search
$str = "Hi abc is abc123"; 

//Find all matches (/g)
preg_match_all($re, $str, $matches);

//Show matches in array
print_r($matches[0]);

将输出：

Array ( [0] => abc [1] => abc123 )

获取与正则表达式匹配的不完整单词

Get incomplete word matched with regular expression

php

preg-match