在 shell 脚本上需要一些帮助(使用 grep 命令)
Need some help on shell scipt (using grep command)
我有一个日志文件,我正在尝试编写一个 shell 脚本来在多行文件中查找多个字符串。
例如,如果我在日志中同时看到短语 "class=com.comcast.parker.GetCurrentAudioLanguageResponse" 和 "status:OK",我应该打印 getAudioLanguage SUCCESSFUL 否则 getAudioLanguage FAILED。所以我的 shell 脚本是这样的:
脚本文件:
logfile=
if grep "{\"class\":\"com.comcast.parker.GetCurrentAudioLanguageResponse\"" jags.txt | grep "{\"status\":\"OK\"" | wc -l ; then
echo "getAudioLanguage SUCCESSFUL"
fi
if grep "{\"class\":\"com.comcast.parker.GetCurrentAudioLanguageResponse\"" $logfile | grep -q "GENERAL_ERROR" | wc -l ; then
echo "getAudioLanguage FAILED"
fi
在日志中,我得到的状态为 GENERAL_ERROR,因此它应该打印 FAILED,但输出显示为 getAudioLanguage SUCCESSFUL ..
对此有任何帮助吗?
日志文件:
160125-11:11:28.442500 [mod=SYS, lvl=INFO] [tid=2332] ======= Message is onRPCCall ======>
160125-11:11:28.442614 [mod=SYS, lvl=INFO] [tid=2332] Entering onRPCCallEvent for request ---> getAudioLanguage
160125-11:11:28.442845 [mod=SYS, lvl=INFO] [tid=2332] Received json request = {"event":1,"handler":1,"name":"onRPCCall","params":{"callGUID":"d75a5bab-6b29-4ab4-9f7e-3cf32d4a05b1","callParams":[{"getAudioLanguage":{}}],"class":"com.comcast.xre.events.XRERPCCallInfo","destinationSessionGUID":"ab00ebea-5f63-4619-9877-273a2bceea1d","method":"getAudioLanguage","sourceSessionGUID":"ab00ebea-5f63-4619-9877-273a2bceea1d"},"phase":"STANDARD","source":1}
160125-11:11:28.442920 [mod=SYS, lvl=INFO] [tid=2332] GetCurrentAudioLanguage : Entered
160125-11:11:28.442968 [mod=SYS, lvl=INFO] [tid=2332] pMainPlayer is NULL.
160125-11:11:28.443012 [mod=SYS, lvl=INFO] [tid=2332] getAudioLanguage: Get Audio Language returned ��v`> T�= T0~�t
160125-11:11:28.443676 [mod=SYS, lvl=INFO] [tid=2332] ====== Response sending is {"appId":1,"command":"CALL","commandIndex":5,"method":"generateAppEvent","params":[{"class":"com.comcast.xre.events.XREOutgoingEvent","name":"onRPCReturn","params":{"callGUID":"d75a5bab-6b29-4ab4-9f7e-3cf32d4a05b1","class":"com.comcast.xre.events.XRERPCReturnInfo","destinationSessionGUID":"ab00ebea-5f63-4619-9877-273a2bceea1d","method":"getAudioLanguage","returnVal":{"class":"com.comcast.parker.GetCurrentAudioLanguageResponse","status":"GENERAL_ERROR","statusMessage":"Getting Current Audio Language was unsuccessful."},"sourceSessionGUID":"ab00ebea-5f63-4619-9877-273a2bceea1d"}},"ab00ebea-5f63-4619-9877-273a2bceea1d"],"targetId":1,"targetPath":"","timestamp":0}
您可以使用单个 awk
而不是多个 grep
:
awk '/{"class":"com\.comcast\.parker\.GetCurrentAudioLanguageResponse"/{
exit ([=10=] !~ /"status":"GENERAL_ERROR"/)}' file && echo "getAudioLanguage FAILED"
awk '/{"class":"com\.comcast\.parker\.GetCurrentAudioLanguageResponse"/{
exit ([=10=] !~ /"status":"OK"/)}' file && echo "getAudioLanguage SUCCESSFUL"
假设您的搜索模式编写正确,那么您可以使用如下内容:
if grep pattern_one file | grep -q pattern_two; then
echo "getAudioLanguage SUCCESSFUL"
fi
这会过滤第一个模式的输出并使用 grep -q
,其退出状态指示第二个模式是否也匹配。
也就是说,您似乎在尝试解析 JSON。如果可能的话,最好使用 jq
之类的东西。
我有一个日志文件,我正在尝试编写一个 shell 脚本来在多行文件中查找多个字符串。
例如,如果我在日志中同时看到短语 "class=com.comcast.parker.GetCurrentAudioLanguageResponse" 和 "status:OK",我应该打印 getAudioLanguage SUCCESSFUL 否则 getAudioLanguage FAILED。所以我的 shell 脚本是这样的:
脚本文件:
logfile=
if grep "{\"class\":\"com.comcast.parker.GetCurrentAudioLanguageResponse\"" jags.txt | grep "{\"status\":\"OK\"" | wc -l ; then
echo "getAudioLanguage SUCCESSFUL"
fi
if grep "{\"class\":\"com.comcast.parker.GetCurrentAudioLanguageResponse\"" $logfile | grep -q "GENERAL_ERROR" | wc -l ; then
echo "getAudioLanguage FAILED"
fi
在日志中,我得到的状态为 GENERAL_ERROR,因此它应该打印 FAILED,但输出显示为 getAudioLanguage SUCCESSFUL ..
对此有任何帮助吗?
日志文件:
160125-11:11:28.442500 [mod=SYS, lvl=INFO] [tid=2332] ======= Message is onRPCCall ======>
160125-11:11:28.442614 [mod=SYS, lvl=INFO] [tid=2332] Entering onRPCCallEvent for request ---> getAudioLanguage
160125-11:11:28.442845 [mod=SYS, lvl=INFO] [tid=2332] Received json request = {"event":1,"handler":1,"name":"onRPCCall","params":{"callGUID":"d75a5bab-6b29-4ab4-9f7e-3cf32d4a05b1","callParams":[{"getAudioLanguage":{}}],"class":"com.comcast.xre.events.XRERPCCallInfo","destinationSessionGUID":"ab00ebea-5f63-4619-9877-273a2bceea1d","method":"getAudioLanguage","sourceSessionGUID":"ab00ebea-5f63-4619-9877-273a2bceea1d"},"phase":"STANDARD","source":1}
160125-11:11:28.442920 [mod=SYS, lvl=INFO] [tid=2332] GetCurrentAudioLanguage : Entered
160125-11:11:28.442968 [mod=SYS, lvl=INFO] [tid=2332] pMainPlayer is NULL.
160125-11:11:28.443012 [mod=SYS, lvl=INFO] [tid=2332] getAudioLanguage: Get Audio Language returned ��v`> T�= T0~�t
160125-11:11:28.443676 [mod=SYS, lvl=INFO] [tid=2332] ====== Response sending is {"appId":1,"command":"CALL","commandIndex":5,"method":"generateAppEvent","params":[{"class":"com.comcast.xre.events.XREOutgoingEvent","name":"onRPCReturn","params":{"callGUID":"d75a5bab-6b29-4ab4-9f7e-3cf32d4a05b1","class":"com.comcast.xre.events.XRERPCReturnInfo","destinationSessionGUID":"ab00ebea-5f63-4619-9877-273a2bceea1d","method":"getAudioLanguage","returnVal":{"class":"com.comcast.parker.GetCurrentAudioLanguageResponse","status":"GENERAL_ERROR","statusMessage":"Getting Current Audio Language was unsuccessful."},"sourceSessionGUID":"ab00ebea-5f63-4619-9877-273a2bceea1d"}},"ab00ebea-5f63-4619-9877-273a2bceea1d"],"targetId":1,"targetPath":"","timestamp":0}
您可以使用单个 awk
而不是多个 grep
:
awk '/{"class":"com\.comcast\.parker\.GetCurrentAudioLanguageResponse"/{
exit ([=10=] !~ /"status":"GENERAL_ERROR"/)}' file && echo "getAudioLanguage FAILED"
awk '/{"class":"com\.comcast\.parker\.GetCurrentAudioLanguageResponse"/{
exit ([=10=] !~ /"status":"OK"/)}' file && echo "getAudioLanguage SUCCESSFUL"
假设您的搜索模式编写正确,那么您可以使用如下内容:
if grep pattern_one file | grep -q pattern_two; then
echo "getAudioLanguage SUCCESSFUL"
fi
这会过滤第一个模式的输出并使用 grep -q
,其退出状态指示第二个模式是否也匹配。
也就是说,您似乎在尝试解析 JSON。如果可能的话,最好使用 jq
之类的东西。