如何在 xml 中使用命名空间

Question

下面是xml

<?xml version="1.0" encoding="UTF-8"?>
<hotels>
<hotel>
    <rooms>
        <room>
            <rates>
                <rate id="1" adults="1" child="0"></rate>
                <rate id="2" adults="2" child="0"></rate>
                <rate id="3" adults="1" child="0"></rate>
            </rates>
        </room>
        <room>
            <rates>
                <rate id="4" adults="1" child="0"></rate>
                <rate id="5" adults="2" child="0"></rate>
                <rate id="6" adults="2" child="0"></rate>
            </rates>
        </room>
    </rooms>
</hotel>
</hotels>

我试试下面的xslt。 XSLT 工作正常。我得到了我需要的结果

<?xml version="1.0" encoding="ISO-8859-1"?>
        <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:output method="xml" indent="yes" omit-xml-declaration="yes"/>

            <xsl:key name="by-occupancy" match="rooms/room/rates/rate" use="concat(generate-id(parent::rooms),\'|\',@adults)"/>

            <xsl:template match="hotels/hotel">
                <hotel>
                <xsl:apply-templates select="rooms/room/rates/rate[generate-id() = generate-id(key(\'by-occupancy\', concat(generate-id(parent::rooms),\'|\',@adults))[1])]" mode="fun_options"/>
                </hotel>
            </xsl:template>

            <xsl:template match="rate" mode="fun_options">
            <rates>
                <xsl:for-each select="key(\'by-occupancy\', concat(generate-id(parent::rooms),\'|\',@adults))">
                <rate><xsl:value-of select="@id"/>-<xsl:value-of select="@adults"/></rate>
                </xsl:for-each>
            </rates>
            </xsl:template>

        </xsl:stylesheet>

但是当我在 xml 中应用 xmlns:xsi 时。

结果空白

<?xml version="1.0" encoding="UTF-8"?>
<hotels xmlns="http://www.test.com/schemas/messages" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" schemaLocation="http://www.test.com/schemas/messages">
<hotel >
    <rooms>
        <room>
            <rates>
                <rate id="1" adults="1" child="0"></rate>
                <rate id="2" adults="2" child="0"></rate>
                <rate id="3" adults="1" child="0"></rate>
            </rates>
        </room>
        <room>
            <rates>
                <rate id="4" adults="1" child="0"></rate>
                <rate id="5" adults="2" child="0"></rate>
                <rate id="6" adults="2" child="0"></rate>
            </rates>
        </room>
    </rooms>
</hotel>
</hotels>

下面的 xslt 我正在尝试。我在这里应用 exclude-result-prefixes="ms xsi"

    <?xml version="1.0" encoding="ISO-8859-1"?>
        <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:ms="http://www.test.com/schemas/messages" exclude-result-prefixes="ms xsi">
  <xsl:output method="xml" indent="yes" omit-xml-declaration="yes"/>

            <xsl:key name="by-occupancy" match="ms:rooms/ms:room/ms:rates/ms:rate" use="concat(generate-id(parent::ms:rooms),\'|\',@adults)"/>

            <xsl:template match="ms:hotels/ms:hotel">
                <hotel>
                <xsl:apply-templates select="ms:rooms/ms:room/ms:rates/ms:rate[generate-id() = generate-id(key(\'by-occupancy\', concat(generate-id(parent::ms:rooms),\'|\',@adults))[1])]" mode="fun_options"/>
                </hotel>
            </xsl:template>

            <xsl:template match="ms:rate" mode="fun_options">
            <rates>
                <xsl:for-each select="key(\'by-occupancy\', concat(generate-id(parent::ms:rooms),\'|\',@adults))">
                <rate><xsl:value-of select="@id"/>-<xsl:value-of select="@adults"/></rate>
                </xsl:for-each>
            </rates>
            </xsl:template>

        </xsl:stylesheet>

我需要如下结果

<hotel>
  <rates>
    <rate>1-1</rate>
    <rate>3-1</rate>
    <rate>4-1</rate>
  </rates>
  <rates>
    <rate>2-2</rate>
    <rate>5-2</rate>
    <rate>6-2</rate>
  </rates>
</hotel>

Answer 1

我完全看不出这些转义字符串是如何编译的。而且您尝试在密钥中使用的 parent 不存在，所以我认为您需要一个祖先：

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:ms="http://www.test.com/schemas/messages" exclude-result-prefixes="ms xsi">
  <xsl:output method="xml" indent="yes" omit-xml-declaration="yes"/>

            <xsl:key name="by-occupancy" match="ms:rooms/ms:room/ms:rates/ms:rate" use="concat(generate-id(ancestor::ms:rooms),'|',@adults)"/>

            <xsl:template match="ms:hotels/ms:hotel">
                <hotel>
                <xsl:apply-templates select="ms:rooms/ms:room/ms:rates/ms:rate[generate-id() = generate-id(key('by-occupancy', concat(generate-id(ancestor::ms:rooms),'|',@adults))[1])]" mode="fun_options"/>
                </hotel>
            </xsl:template>

            <xsl:template match="ms:rate" mode="fun_options">
            <rates>
                <xsl:for-each select="key('by-occupancy', concat(generate-id(ancestor::ms:rooms),'|',@adults))">
                <rate><xsl:value-of select="@id"/>-<xsl:value-of select="@adults"/></rate>
                </xsl:for-each>
            </rates>
            </xsl:template>

        </xsl:stylesheet>

如何在 xml 中使用命名空间

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