设置 Android 片段进入和退出过渡?

Setting Android fragment enter and exit transitions?

我正在尝试为 DialogFragment 设置进入和退出过渡,这看起来很简单。这是我的 DrinkDetailActivity 创建对话框的代码:

    fab.setOnClickListener(new View.OnClickListener(){
        @Override
        public void onClick(View v) {
            //create and display the dialog
            DialogFragment orderFragment = new OrderDrinkDialogFragment();

            //set the slide transition for the fragment
            Transition dialSlide = new Slide();
            dialSlide.setDuration(300);

            orderFragment.setEnterTransition(dialSlide);
            orderFragment.setExitTransition(dialSlide);
            orderFragment.show(getFragmentManager(), "order");
        }
    });

这是我的 OrderDrinkDialogFragment Class:

中的代码
public class OrderDrinkDialogFragment extends DialogFragment
{
    @Override
    public Dialog onCreateDialog(Bundle savedInstanceState)
    {
        AlertDialog.Builder builder = new AlertDialog.Builder(DrinkDetailActivity.activity);

        //set up the Linear Layout of the dialog
        LinearLayout layout = new LinearLayout(DrinkDetailActivity.activity);
        LinearLayout.LayoutParams params = new LinearLayout.LayoutParams(LinearLayout.LayoutParams.MATCH_PARENT,
                                                                     LinearLayout.LayoutParams.WRAP_CONTENT);
        layout.setOrientation(LinearLayout.VERTICAL);
        layout.setLayoutParams(params);

        //set up the EditText view
        EditText nameField = new EditText(DrinkDetailActivity.activity);
        nameField.setHint(R.string.dialog_name_hint);

        //add the EditText view to the layout
        layout.addView(nameField, new LinearLayout.LayoutParams(LinearLayout.LayoutParams.MATCH_PARENT,
                                                            LinearLayout.LayoutParams.WRAP_CONTENT));

        //set layout as the view of the dialog
        builder.setView(layout);

        return builder.create();
    }
}

DrinkDetailActivity.activity 只是 this 来自 DrinkDetailActivity 的实例。出于某种原因,当我 show() 它或当它被关闭时,对话框不会转换,它只是弹出和弹出视图。 This 教程在为我的应用程序的其余部分弄清楚 Activity 转换方面提供了很多帮助,并且我按照它所说的相同的片段转换说明进行操作。我做错了什么?

DialogFragment is not just a Dialog but also a Fragment, see Basic Dialog 了解更多使用方法。您在 Fragment 中使用了 onCreateDialog,这可能是导致问题的原因。因此,使用 onCreateView 创建片段对话框视图。

希望这个回答对您有所帮助。

这适用于 me.My 向上滑动动画是

<?xml version="1.0" encoding="utf-8"?> <set xmlns:android="http://schemas.android.com/apk/res/android" >

    <translate
        android:duration="@android:integer/config_mediumAnimTime"
        android:fromYDelta="100%"
        android:interpolator="@android:anim/accelerate_interpolator"
        android:toXDelta="0" />

</set>

我的幻灯片动画是

<?xml version="1.0" encoding="utf-8"?>
<set xmlns:android="http://schemas.android.com/apk/res/android" >

    <translate
        android:duration="@android:integer/config_mediumAnimTime"
        android:fromYDelta="0%p"
        android:interpolator="@android:anim/accelerate_interpolator"
        android:toYDelta="100%p" />

</set>

在您的样式中添加这个

<style name="DialogAnimation">
    <item name="android:windowEnterAnimation">@anim/slide_up</item>
    <item name="android:windowExitAnimation">@anim/slide_down</item>
</style>

现在终于在你的 onCreateDialog() 对话框片段中添加这个

public Dialog onCreateDialog(Bundle savedInstanceState) 
{
    final Dialog dialog = super.onCreateDialog(savedInstanceState);
    dialog.getWindow().getAttributes().windowAnimations = R.style.DialogAnimation;
    return dialog;
}

您需要编写一种样式来在任何 window 上显示动画,例如 Dialog

<style name="AnimDialog" parent="@android:style/Theme.Dialog">
    <item name="android:windowAnimationStyle">@style/DialogAnimation</item>
</style>

<style name="DialogAnimation">
    <item name="android:windowEnterAnimation">@anim/fadein</item>
    <item name="android:windowExitAnimation">@anim/fadeout</item>
</style>

对于你的对话框,你需要像这样实例化

Dialog animatedDialog = new Dialog(MainActivity.this,R.style.AnimDialog);