计算连续行 - SQL Server 2008

Question

我需要根据其他列中的值计算连续的行数。

关于 SQL 我完全是个新手 - 所以如果有什么不清楚的地方请问。

我有 SQL Server 2008，所以 LEAD() 和 LAG() 没有发挥作用，与 OVER() 相同，window 大小基于分区。

示例数据集：

SLOT                    Blocked 
-------------------------------
2015-02-09 07:00:00.000 0
2015-02-09 07:15:00.000 0
2015-02-09 07:30:00.000 0
2015-02-09 07:45:00.000 1
2015-02-09 08:00:00.000 1
2015-02-09 08:15:00.000 1
2015-02-09 08:30:00.000 0
2015-02-09 08:45:00.000 0
2015-02-09 09:00:00.000 0
2015-02-09 09:15:00.000 0
2015-02-09 09:30:00.000 1
2015-02-09 09:45:00.000 1
2015-02-09 10:00:00.000 1
2015-02-09 10:15:00.000 1
2015-02-09 10:30:00.000 0
2015-02-09 10:45:00.000 0
2015-02-09 11:00:00.000 0
2015-02-09 11:15:00.000 0
2015-02-09 11:30:00.000 0
2015-02-09 11:45:00.000 0
2015-02-09 12:00:00.000 0

数据按SLOT排序。我想计算分区 where Blocked = 0.

上的行数

我想得到的结果集：

SLOT                    Blocked     RowNum
-------------------------------------------
2015-02-09 07:00:00.000 0           1
2015-02-09 07:15:00.000 0           2
2015-02-09 07:30:00.000 0           3
2015-02-09 07:45:00.000 1           0
2015-02-09 08:00:00.000 1           0
2015-02-09 08:15:00.000 1           0
2015-02-09 08:30:00.000 0           1
2015-02-09 08:45:00.000 0           2
2015-02-09 09:00:00.000 0           3
2015-02-09 09:15:00.000 0           4
2015-02-09 09:30:00.000 1           0
2015-02-09 09:45:00.000 1           0
2015-02-09 10:00:00.000 1           0
2015-02-09 10:15:00.000 1           0
2015-02-09 10:30:00.000 0           1
2015-02-09 10:45:00.000 0           2
2015-02-09 11:00:00.000 0           3
2015-02-09 11:15:00.000 0           4
2015-02-09 11:30:00.000 0           5
2015-02-09 11:45:00.000 0           6
2015-02-09 12:00:00.000 0           7

提前致谢！

Answer 1

对于SQL Server 2008你可以这样解决

SELECT Slot
      ,Blocked
      ,CASE WHEN Blocked = 0
                 THEN ROW_NUMBER() OVER
                 (PARTITION BY rt.RunningTotal ORDER BY Slot)
            ELSE 0 END RowNum
FROM Table1 t
CROSS APPLY (SELECT ISNULL(SUM(Blocked), 0) RunningTotal
             FROM Table1
             WHERE Slot < t.Slot
            ) rt
ORDER BY Slot

（将表 1 替换为您的 table 姓名）

SQL Fiddle: http://sqlfiddle.com/#!3/659a0/28

Answer 2

由于您使用的是sql server 2008，所以需要使用row_number() over。计算有点复杂，但是这个脚本可以从 sql server 2005 运行。

;WITH CTE AS
(
SELECT SLOT, row_number() over (order by SLOT)-
row_number() over (partition by blocked order by SLOT) x, blocked
 FROM 
-- replace these lines with your real table
--start test tabel
(values 
(cast( '2015-02-09 07:00:00.000' as datetime), 0)
,('2015-02-09 07:15:00.000', 0),('2015-02-09 07:30:00.000', 0)
,('2015-02-09 07:45:00.000', 1),('2015-02-09 08:00:00.000', 1)
,('2015-02-09 08:15:00.000', 1),('2015-02-09 08:30:00.000', 0)
,('2015-02-09 08:45:00.000', 0),('2015-02-09 09:00:00.000', 0)
,('2015-02-09 09:15:00.000', 0),('2015-02-09 09:30:00.000', 1)
,('2015-02-09 09:45:00.000', 1),('2015-02-09 10:00:00.000', 1)
,('2015-02-09 10:15:00.000', 1),('2015-02-09 10:30:00.000', 0)
,('2015-02-09 10:45:00.000', 0),('2015-02-09 11:00:00.000', 0)
,('2015-02-09 11:15:00.000', 0),('2015-02-09 11:30:00.000', 0)
,('2015-02-09 11:45:00.000', 0),('2015-02-09 12:00:00.000', 0)) x(SLOT,Blocked )
-- end test tabel
)
SELECT 
  SLOT, 
  BLOCKED, 
  CASE WHEN blocked = 0 
    THEN
      row_number() over (partition by x, blocked order by slot) 
    ELSE 0 end ROWNUMBER
FROM cte
ORDER BY slot

Answer 3

有趣的问题..!!

我能够使用以下代码实现此目的：

    CREATE TABLE #TestTable(SLOT DATETIME,BLOCKED INT);

    INSERT #TestTable(SLOT,BLOCKED)
    VALUES
    ('2015-02-09 07:00:00.000' ,0),
    ('2015-02-09 07:15:00.000' ,0),
    ('2015-02-09 07:30:00.000' ,0),
    ('2015-02-09 07:45:00.000' ,1),
    ('2015-02-09 08:00:00.000' ,1),
    ('2015-02-09 08:15:00.000' ,1),
    ('2015-02-09 08:30:00.000' ,0),
    ('2015-02-09 08:45:00.000' ,0),
    ('2015-02-09 09:00:00.000' ,0),
    ('2015-02-09 09:15:00.000' ,0),
    ('2015-02-09 09:30:00.000' ,1),
    ('2015-02-09 09:45:00.000' ,1),
    ('2015-02-09 10:00:00.000' ,1),
    ('2015-02-09 10:15:00.000' ,1),
    ('2015-02-09 10:30:00.000' ,0),
    ('2015-02-09 10:45:00.000' ,0),
    ('2015-02-09 11:00:00.000' ,0),
    ('2015-02-09 11:15:00.000' ,0),
    ('2015-02-09 11:30:00.000' ,0),
    ('2015-02-09 11:45:00.000' ,0),
    ('2015-02-09 12:00:00.000' ,0)


    SELECT *
    FROM #TestTable
    ORDER BY SLOT


    ;WITH TestTableVw AS
    (SELECT SLOT,BLOCKED,ROW_NUMBER() OVER(ORDER BY  SLOT) RNum
     FROM #TestTable
    )
    SELECT T.SLOT,T.BLOCKED,CASE WHEN T.BLOCKED=0 THEN V1.RNum-ISNULL((SELECT MAX(V2.RNum) FROM TestTableVw V2 WHERE V2.RNum<V1.RNum AND V2.BLOCKED=1),0) ELSE 0 END
    FROM #TestTable T
    JOIN TestTableVw V1 ON T.SLOT=V1.SLOT

    DROP TABLE #TestTable;

我希望这会有所帮助..!!

谢谢，

Swapnil

计算连续行 - SQL Server 2008

Counting consecutive rows - SQL Server 2008

tsql

sql-server

sql-server-2008