如何打破列表中的元组括号？

Question

我有一个数据列表：

[[], [], [(2, 3), (2, 7), (3, 2), (7, 2)], [(2, 3), (3, 2), (3, 7), (7, 3)], [], [], [], [(2, 7), (3, 7), (7, 2), (7, 3)], [], []]

我想去掉元组中的括号，这样 [(2, 3), (2, 7), (3, 2), (7, 2)] 就会变成 (2,3,2,7,3,2,7,2)。

有快捷方式吗？

Answer 1

您要展平列表。在 python 中，您可以使用复合列表理解来做到这一点

data = [(2, 3), (3, 2), (3, 7), (7, 3)]
flattend = [item for lst in data for item in lst]

Answer 2

您可以使用 itertools.chain:

In [6]: l = [[], [], [(2, 3), (2, 7), (3, 2), (7, 2)], [(2, 3), (3, 2), (3, 7), (7, 3)], [], [], [], [(2, 7), (3, 7), (7, 2), (7, 3)], [], []]

In [7]: [tuple(itertools.chain(*el)) for el in l]
Out[7]: 
[(),
 (),
 (2, 3, 2, 7, 3, 2, 7, 2),
 (2, 3, 3, 2, 3, 7, 7, 3),
 (),
 (),
 (),
 (2, 7, 3, 7, 7, 2, 7, 3),
 (),
 ()]

如何打破列表中的元组括号？

How to break the tuple brackets within a list?

python