用于访问 JavaScript 中指针对象内字段的基本 Parse 查询

Basic Parse query to access a field inside a pointer object in JavaScript

我有一个名为 "Current1" 的 table,我将用户的对象保存为这样的指针:

当我点击这个指针时,我指向 _User table。现在我正在尝试做非常简单的查询。我需要访问用户指针内的用户名,然后在 _User table.

中更新一些内容

我的问题现在是使用指针访问“_User”table中的'username':

var aveGame2 = Parse.Object.extend("Current1");
var query2 = new Parse.Query(aveGame2);
query2.include("user");
query2.find({
    success: function(results) {

        for (var i = 0; i < results.length; i++) 
        {
            var object = results[i];
            //....
            var user = object.get('user');

            var username = user.get('username'); //<--Error is pointing to this line

            //More operation

            if(True)//Some conditions
            {
                Parse.Cloud.useMasterKey();
                var query = new Parse.Query(Parse.User);
                query.equalTo("username", username);

                // Get the first user which matches the above constraints.
                query.first({
                    success: function(anotherUser) {

                        anotherUser.set("prize", 10);

                        // Save the user.
                        anotherUser.save(null, {
                          success: function(anotherUser) {
                          // The user was saved successfully.
                          response.success("Successfully updated user.");
                        },
                        error: function(gameScore, error) {
                           // The save failed.
                           // error is a Parse.Error with an error code and description.
                           response.error("Could not save changes to user.");
                        }
                    });
                },
             error: function(error) {
                 response.error("Could not find user.");
             }
});

错误:

[Error]: TypeError: Cannot call method 'get' of undefined
    at e.query2.find.success

在检查每个字段数小时后,我意识到我没有为 _User table 设置 ACL,因为 Public 读取。这可能会对其他人有所帮助。