长到十六进制字符串字符数

Question

你好我正在尝试构建一个随机的 16 个字符的十六进制，为此我尝试了一个 Long.toHexString(new Random().nextLong() 我的假设是它总是 return 一个 16 个字符的字符串，我说得对吗？（一旦它 returned 15 个字符）

Answer 1

参考 Javadoc of the method in question 应该是您的第一个停靠港：

This value is converted to a string of ASCII digits in hexadecimal (base 16) with no extra leading 0s

所以不，它不会总是 16 个字符。

但是，您可以打印 16 个字符的大写十六进制字符串，前导零，使用：

String.format("%016X", longValue)

Answer 2

查看 toHexString(long i) 的 javadoc（强调我的）。

public static String toHexString(long i)

Returns a string representation of the long argument as an unsigned integer in base 16.

The unsigned long value is the argument plus 2⁶⁴ if the argument is negative; otherwise, it is equal to the argument. This value is converted to a string of ASCII digits in hexadecimal (base 16) with no extra leading 0s. If the unsigned magnitude is zero, it is represented by a single zero character '0' ('\u0030'); otherwise, the first character of the representation of the unsigned magnitude will not be the zero character.

事实证明，它不会总是 16 个字符长。但是，如果你愿意，你可以用零填充：

import java.util.Random;

class Main {
    public static void main(String[] args) {
        String hex16Chars = String.format("%016X", new Random().nextLong());
        System.out.println(hex16Chars + ", len: " + hex16Chars.length());
    }
}

您会看到长度始终如预期的那样为 16。

事实证明，偷看文档确实有帮助！ :)

长到十六进制字符串字符数

Long to hex String number of characters

java

hex

long-integer