如何过滤 jira-cli getIssueList 报告

Question

jira.sh --server http://jira.########.###:8080 --password ######### --action getIssueList --jql "project = SetRix order by Created desc" --user ##### --project SetRix --limit 15 --dateFormat "MM-dd" --outputFormat 2 --suppressId --columns "Key,Summary,Created,Status"

以上是我的 jira-cli 查询，这是报告：

"STR-120","Do not report status for the jobwhen it is terminated","02-13","Done"
"STR-119","timeshift memory leak - high CPU","02-12","To Do"
"STR-118","Timeshift directory per-stream","02-12","To Do"
"STR-117","Restart button needed","02-12","To Do"
"STR-116","Create 'clone' function for presets","02-12","Done"

如何过滤报告以仅查看 "To Do" 个条目？

我不想 grep，我想使用 jira 查询。

Answer 1

基于 JQL 和输出列，我会说：

project = SetRix AND Status = 'To Do' order by Created desc

即只需明确要求仍然 To Do

的项目

如何过滤 jira-cli getIssueList 报告

How to filter jira-cli getIssueList report

jira

jira-cli