Yii2 GridView 为外国 Table 的相关 Table 实现值过滤和排序

Question

我有 3 个表：

CREATE TABLE tabCve
(
    intCveID INTEGER NOT NULL AUTO_INCREMENT,
    strNumber VARCHAR(20) NOT NULL,
    fltScore FLOAT(0),
    strDescription TEXT,
    datImported DATETIME NOT NULL DEFAULT NOW(),
    intCvePhaseID INTEGER,
    intCveTypeID INTEGER,
    PRIMARY KEY (intCveID),
    KEY (intCvePhaseID),
    KEY (intCveTypeID)

) ;


CREATE TABLE tabProgress
(
    intProgressID INTEGER NOT NULL AUTO_INCREMENT,
    intProgressCveID INTEGER NOT NULL,
    intProgressUserID INTEGER NOT NULL,
    intProgressStateID INTEGER NOT NULL,
    intProgressCategoryID INTEGER,
    datCreated DATETIME NOT NULL,
    PRIMARY KEY (intProgressID),
    KEY (intProgressCategoryID),
    KEY (intProgressCveID),
    KEY (intProgressStateID),
    KEY (intProgressUserID)

) ;

CREATE TABLE tabCategory
(
    intCategoryID INTEGER NOT NULL AUTO_INCREMENT,
    strCategory VARCHAR(50) NOT NULL,
    PRIMARY KEY (intCategoryID)

) ;

我用 Gii 为 tabCve 创建了一个 CRUD。我成功地为 intCvePhaseID

等引用表中的字段实现了过滤和排序功能

现在我想通过 tabProgress 为 tabCategory 实现这个 tabCve和tabProgress之间的关系是1比1。

我必须如何在我的 SearchModel 中实现它？

到目前为止我做了什么：

模型中：

public function getProgress()
{
    return $this->hasOne(TabProgress::className(),['intProgressCveID' => 'intCveID'])->with(['category']);
}   

public function getCategory()
{
    return $this->hasOne(TabCategory::className(),['intCategoryID' => 'intProgressCategoryID']);
}

在搜索模型中：

public 函数搜索($params) { $query = TabCve::find();

$dataProvider = new ActiveDataProvider([
    'query' => $query,
    'sort'=> ['defaultOrder' => ['strNumber' => 'DESC']],
]);

$query->select(["intCveID","strNumber","fltScore","strDescription","datImported","intCvePhaseID","intCveTypeID",'progress.intProgressCategoryID']);
$query->joinWith("phase");
$query->joinWith("type");
$query->joinWith("progress");
$query->Where(['not like', 'strDescription', '** RESERVED **%', false]);
$query->andWhere(['not like', 'strDescription', '** REJECT **%', false]);
//$query->andWhere(["intProgressID" => null]);

$this->load($params);

if (!$this->validate()) {
    // uncomment the following line if you do not want to return any records when validation fails
    // $query->where('0=1');
    return $dataProvider;
}

$query->andFilterWhere([
    'intCveID' => $this->intCveID,
    'fltScore' => $this->fltScore,
    'datImported' => $this->datImported,
]);

$query->andFilterWhere(['like', 'strNumber', $this->strNumber])
    ->andFilterWhere(['like', 'strDescription', $this->strDescription])
    ->andFilterWhere(['like','tabPhase.strPhase', $this->intCvePhaseID])
    ->andFilterWhere(['like','datImported',$this->datImported])
    ->andFilterWhere(['like','tabType.strType', $this->intCveTypeID])
    ->andFilterWhere(['like','tabProgress.tabCategory.strCategory', $this->intCveTypeID])
    ;
return $dataProvider;
}

我该如何实现这些行中的字段：

$query->select(["intCveID","strNumber","fltScore","strDescription","datImported","intCvePhaseID","intCveTypeID",'progress.intProgressCategoryID']);

和：

->andFilterWhere(['like','tabProgress.tabCategory.strCategory', $this->intCveTypeID])

Answer 1

在您的 seachModel 中，您需要 public var 用于过滤器 ..

不需要 select 因为这是由 find.. 提供的，最好重新排列下面的代码

$query->select(["intCveID","strNumber","fltScore","strDescription","datImported","intCvePhaseID","intCveTypeID",'progress.intProgressCategoryID']);
$query->joinWith("phase");
$query->joinWith("type");
$query->joinWith("progress");
$query->Where(['not like', 'strDescription', '** RESERVED **%', false]);
$query->andWhere(['not like', 'strDescription', '** REJECT **%', false]);

以本文档中建议的另一种方式

http://www.yiiframework.com/wiki/621/filter-sort-by-calculated-related-fields-in-gridview-yii-2-0/

http://www.yiiframework.com/wiki/653/displaying-sorting-and-filtering-model-relations-on-a-gridview/

对于

->andFilterWhere(['like','tabProgress.tabCategory.strCategory', 
        $this->intCveTypeID])

上面 link 中提供的示例建议使用 getter 来检索您需要的列，并在 andFilterWhere

中也使用此 getter

这样 :

在你的模型中你已经有一个

public function getCategory()
{
    return $this->hasOne(TabCategory::className(),
     ['intCategoryID' =>   'intProgressCategoryID']);
}

然后你可以为 strCategory

构建一个 getter

public function getStr_category() {
    return $this->category->strCategory;
}

此时您可以使用

在模型搜索中检索数据

->andFilterWhere(['like','str_category', $this->intCveTypeID])

Answer 2

访问有关此问题的完整教程：

http://www.yiiframework.com/wiki/851/yii2-gridview-sorting-and-searching-with-a-junction-table-column-many-to-many-relationship/

根据本教程，您应该： 1. 在搜索模型中将相关 table 属性设置为 public，如下所示：

public $groupname;

2。在规则中包含属性：

    public function rules() {
        return [
            [['id', 'gender', 'status', 'sentstatus'], 'integer'],
            [['groupname', 'addeddate', 'updateddate'], 'safe'],
        ];
    }

将搜索模型中函数 search() 中的默认查询更改为以下代码：

public function search($params) {
$query = Contacts::find()->innerJoinWith('groups', true);

并在 andfilterwhere 中添加想要的属性。像这样：

$query->andFilterWhere(['like', 'firstname', $this->firstname])
               ... 
                ->andFilterWhere(['like', 'groupname', $this->groupname]);

在您的 view class 和 Gridview 中，您想要的列应该是这样的：

'columns' => [
                ...
            [
                'attribute' => 'tags',
                'format' => 'raw',
                'value' => function ($data) {
                    $groups= '';
                    foreach ($data->groups as $group) {
                        $groups .= '<a href="/group/' . $group->id . '">' .
                        $group->group_name . '</a> | ';
                    }
                    return $groups;
         },
        'filter' => ArrayHelper::map(group::find()->asArray()->all(), 'group_name','group_name'),
                ],

如果 table 关系是 hasOne() 你应该阅读本教程：

http://www.yiiframework.com/wiki/653/displaying-sorting-and-filtering-model-relations-on-a-gridview/

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