php Class 即使在 require_once 文件中也找不到

php Class not found even in require_once file

我有一个奇怪的问题。其 Plans.php 文件中有一些计划 class 包含在主 php 中,但似乎未被系统加载。

看,这是action.php文件

<?php

// action.php gets 3 parameters:
//  - CONTROLLER: one on AUTH, SYSTEM, USER, ADS 
//  - ACTIVITY: one on LOGIN, PLANS, CONTACTS, GUESTS, CONFIG, MESSAGES
//  - ACTION: LIST, VIEW, EDIT, INSERT, UPDATE

include './config/config.php';
include './utils/Connect_db.php';
require_once './model/Plans.php';
require_once './controllers/MainController.php';
require_once './controllers/AuthController.php';
require_once './controllers/UserController.php';
require_once './classes/ValidateUser.php';

if (class_exists('Plans')) {
    error_log('action: Plans exists');
} else {
    error_log('action: Plans NOT exists');
}

if (class_exists('AuthController')) {
    error_log('action: AuthController exists');
} else {
    error_log('action: AuthController NOT exists');
}

$main = new MainController();

?>

我放了一些 class_exists 函数来检查 Plans class 是否加载。

这是 error_log 文件输出:

[13-Feb-2015 01:04:39 Europe/Brussels] action: Plans NOT exists
[13-Feb-2015 01:04:39 Europe/Brussels] action: AuthController exists

显然以后使用计划 class 会导致 计划 class 未找到

这是我的 Plans.php 文件:

<?php

class Plans {

    private $_con;
    private $_sql;

    function __construct($users_id, $plans_id) {

        $this->_con = Connect_db();

        switch(func_num_args()) {
            case 0:
                break;
            case 1: // One argument to be users_id
                $this->_sql = "(SELECT u.users_nic, g.status, p.*"
                ." FROM users u, plans p LEFT JOIN guests g"
                ." ON g.plans_id=p.plans_id AND g.users_id=p.users_id"
                ." WHERE u.users_id=p.users_id AND p.users_id=".$users_id.")"
                    . " UNION"
                    . " (SELECT u.users_nic, g.status, p.*"
                ." FROM plans p, users u, guests g"
                ." WHERE u.users_id=p.users_id AND g.plans_id=p.plans_id"
                ." AND g.users_id=".$_users_id." AND p.users_id!=".$users_id." )"
                    ." ORDER BY día DESC";
                break;
            case 2: // Two arguments to be users_id y plans_id
                $this->_sql = "SELECT u.users_nic, g.status, p.*"
                ." FROM users u, plans p"
                ." LEFT JOIN guests g"
                ." ON g.plans_id=p.plans_id AND g.users_id=".$users_id
                ." WHERE u.users_id=p.users_id AND p.plans_id=".$plans_id;
                break;
        }

    } 

    function __destruct(){
        // TO DO
        mysqli_close($this->_con);
    }

    public function dir() {

        $res = mysqli_query($this->_con, $this->_sql)
            or die("Fallo de Consulta");

        $arrSalida = array();

        while ($fila = mysqli_fetch_array($res)) {
            $arrSalida[] = $fila;
        }

        return $arrSalida;

    }
}
?>

这个class有什么问题?完成切换以使用一个或两个参数实现 __construct 。并且 modelclasses 文件夹存在并且文件名正确。

希望有人能提供帮助。谢谢。

难以置信,问题出在我的 php 代码中的 隐藏字符 中。我删除了该文件并创建了一个新文件,再次输入代码而没有 copy/paste,问题就消失了。可悲的是,我没有保留该文件以使用另一个文本编辑器对其进行分析,因为我可以看到坏字符。