在没有方法的情况下按顺序打印数组

Question

我是一名编码新手，我的 class 最近开始学习数组。我一整天都在为这个程序作业苦苦思索。几天后才到期，但我对此感到非常沮丧。

我们必须打印出一份考试成绩列表以及与之关联的相关 ID。我们必须将测试分数从最高到最低排序，但不修改数组——所以没有数组排序，或任何类似的。 "suggested solution" 表示：

找到最大的分数，跟踪它的下标。
打印此分数以及相应的 ID。
设置那个分数等于它的相反值（这使得它最小得分！）。
重复步骤 1-3，直到处理完所有 21 个分数。
停止并打印一条适当的消息。

我一直在努力遵守这些说明，因为本周剩下的时间里还有其他程序将依赖于此。然而，我的方法是有缺陷的，因为我的代码打印了 26 次迭代的最大分数是 110、238。我在使用这段代码时遇到了很大的麻烦，这让我很沮丧。这是我目前所拥有的：

import java.io.File;
import java.io.FileNotFoundException;
import java.util.Scanner;

public class Prog408a {

    static Scanner inFile = null;
    static Scanner inFile2 = null;

    public static void main (String[]args) {

        try {

            // create scanner to read file
            inFile = new Scanner(new File ("prog408a.dat"));

        } catch (FileNotFoundException e) {
            System.out.println("File not found!");
            System.exit(0);
        }

        int [] ids = new int[26];
        int [] scores = new int[26];

        int first = 0;
        int second = 0;

        int counter = 0;

        int max, maxid, supermax;

        do {

            ids [first] = inFile.nextInt();
            scores [second] = inFile.nextInt();

            first++;
            second++;

        } while (inFile.hasNextInt());


        /* initial values of max, maxid */



        System.out.println("ID\t\tScore");

        maxid = ids[0];
        supermax = scores[0];
        max = scores[0];
        int index=0;

        while (counter < scores.length) {

            for (int x = 0; x < scores.length - 1; x++) { // scroll through the indexes.

                if (scores[x] > max) {

                    max = scores[x];
                    index = x; // keep the index of the biggest number.

                } 

                max = -1 * (scores[index]);

            }

            System.out.println("The maximum score is " + ids[index] + ", " + scores[index]);
            counter++;



        }




    }

}

这是数据文件中的内容。

post.

如有格式错误请见谅

Answer 1

while (counter < scores.length - 1) {
        for (int x = 0; x < scores.length - 1; x++) { // scroll through the indexes.
            if (scores[x] > max) {
                max = scores[x];
                index = x; // keep the index of the biggest number.
            } 
        }
        System.out.println("The maximum score is " + ids[index] + ", " + scores[index]);
        max = -1 * (scores[index]);
        scores[index] = -1 * (scores[index]); // change the value in the original array so it won't find the same max again
        counter++;
}

输出：

ID      Score
The maximum score is 1, 599
The maximum score is 4, 560
The maximum score is 3, 559
The maximum score is 2, 513
The maximum score is 365, 265
The maximum score is 306, 262
The maximum score is 115, 257
The maximum score is 311, 256
The maximum score is 123, 253
The maximum score is 325, 246
The maximum score is 116, 246
The maximum score is 323, 245
The maximum score is 321, 245
The maximum score is 113, 243
The maximum score is 218, 243
The maximum score is 208, 242
The maximum score is 302, 242
The maximum score is 104, 239
The maximum score is 112, 239
The maximum score is 110, 238
The maximum score is 223, 230
The maximum score is 213, 229
The maximum score is 207, 228
The maximum score is 203, 224
The maximum score is 222, 223

您可能想要添加一个小函数，该函数将在 id < 100 开头打印额外的零。

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