MIPS：如何将值存储到数组中

Question

我编写了程序以从用户那里获取 4 个值并存储它。但是我不知道如何将它放入 'list' (.space):

.data 
list:  .space 16
msg: .asciiz "Enter 4 numbers: "
.text

main: 
la $a0,msg # display prompt string
li $v0,4
syscall

li $v0, 5 # read integer 
syscall
add $s0, $v0, $zero #store input1 to s0

li $v0, 5 # read integer 
syscall
add $s1, $v0, $zero #store input2 to s1

li $v0, 5 # read integer 
syscall
add $s2, $v0, $zero #store input3 to s2

li $v0, 5 # read integer 
syscall
add $s3, $v0, $zero #store input4 to s3




exit:    
    li $v0, 10 # exit system call 
sysca

Answer 1

I can't figure out how to put it into the 'list'

通过将数组的基地址加载到某个寄存器，然后使用sw指令将数据存储在那里：

la $a1, list

# ... read the integers ...

sw $s0, 0($a1)
sw $s1, 4($a1)
sw $s2, 8($a1)
sw $s3, 12($a1)

我建议您下载 MIPS32™ Architecture For Programmers 第二卷：MIPS32™ 指令集.

MIPS：如何将值存储到数组中

MIPS: how to store values into array

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