PHP 数组 JSON 没有 []

PHP Arrays to JSON without []

我正在使用 CMS,想将一些 PHP 数组传递给 JSON。我设法做得很好,但问题是它包裹了 [] 数组,而我需要它而不用 [] 将它用作 Mapbox 中的 geojson (https://www.mapbox.com/mapbox-gl-js/example/popup-on-click/).

<?php 
$programme_array = array();
$programmes = $pages->find('parent=programme, sort=sort');
foreach ($programmes as $programme) {
    $title = $programme->title;
    $url = $programme->url;
    $summary = $programme->programme_summary;
    $image = $programme->programme_venue_image->url;
    $long = $programme->programme_location->lng;
    $lat = $programme->programme_location->lat;
    $programme_array[] = array(
        'type' => 'Feature',
        'geometry' => array(
            'type' => 'Point',
            'coordinates' => [$long,$lat]
        ),
        'properties' => array(
            'title' => $title,
            'description' => $summary,
            'image' => $image,
            'url' => $url,
            "marker-symbol" => "music"
        ),
    );

}
$programme_json = json_encode($programme_array, true);
?>

[{"type":"Feature","geometry":{"type":"Point","coordinates":["-1.466439","53.376842"]},"properties":{"title":"Site Gallery","description":"Duis arcu tortor, suscipit eget, imperdiet nec, imperdiet iaculis, ipsum. Donec id justo. Aenean tellus metus, bibendum sed, posuere ac, mattis non, nunc. Suspendisse feugiat. Etiam rhoncus.","image":"\/Freelance\/art-sheffield-2016\/site\/assets\/files\/1032\/site_gallery.jpg","url":"\/Freelance\/art-sheffield-2016\/programme\/site-gallery\/","marker-symbol":"music"}},{"type":"Feature","geometry":{"type":"Point","coordinates":["-1.477881","53.374798"]},"properties":{"title":"Moore Street Substation","description":"","image":null,"url":"\/Freelance\/art-sheffield-2016\/programme\/moore-street-substation\/","marker-symbol":"music"}},{"type":"Feature","geometry":{"type":"Point","coordinates":["-1.459620","53.380562"]},"properties":{"title":"S1 Artspace","description":"","image":null,"url":"\/Freelance\/art-sheffield-2016\/programme\/s1-artspace\/","marker-symbol":"music"}}]

更新

我想出了以下方法,它在格式化方面有效,但它只返回一项而不是三项?

$geojson = array( 'type' => 'FeatureCollection', 'features' => array());

$programmes = $pages->find('parent=programme, sort=sort');
foreach ($programmes as $programme) {

  $marker = array(
    'type' => 'Feature',
    'properties' => array(
      'title' => $programme->title,
      "marker-symbol" => "music"
    ),
    'geometry' => array(
      'type' => 'Point',
      'coordinates' => array( 
        $programme->programme_location->lng,
        $programme->programme_location->lat
      )
    )
  );
  array_push($geojson['features'], $marker);
}
$programme_json = json_encode($marker, JSON_PRETTY_PRINT);

更奇怪的是,如果我将方括号 [ ] 添加到 $marker = array( 有效地使其成为 $marker[] = array( 然后它 returns 所有项目但它有正方形上面有括号。

我陷入了兔子洞的深处...

请先将数组转换为对象,然后再将其编码为 json,这样应删除 []。希望对您有所帮助!!

从变量 $programme_array[] 中删除 [],因此它应该看起来像 $programme_array = array(......................); 并且它会完成工作。事实上,你不需要说 $programme_array[] 因为你已经将它初始化为 $programme_array = array().

您需要在适当的地方而不是在需要对象的地方使用数组。当您需要对象时,您可以使用 stdClass。以下是如何创建一个 PHP 结构,完美编码为 JSON:

<?php

$feature = new stdClass();
$feature->type = 'Feature';
$feature->properties = new stdClass();
$feature->properties->key = 'value';
$feature->geometry = new stdClass();
$feature->geometry->type = 'Point';
$feature->geometry->coordinates = array(0,0);

$json = json_encode($feature);

此处 $json 成立:

"{"type":"Feature","properties":{"key":"value"},"geometry":{"type":"Point","coordinates":[0,0]}}"

当你将它发送给客户端并在 Javascript 中解析它时,它变成:

{
    "type":"Feature",
    "properties": {
         "key":"value"
    },
    "geometry": {
        "type":"Point",
        "coordinates":[0,0]
    }
}

所以现在当您创建 GeoJSON 集合对象时:

<?php

$collection = new stdClass();
$collection->type = 'FeatureCollection';
$collection->features = array();

您可以将 $feature 推入 $collection->features:

$collection->features[] = $feature;

@braw,请检查下面的代码。

$programmes = array('1', '2');
$programme_array = array();
foreach ($programmes as $programme) {

    $programme_array[] = array(
        'type' => 'Feature',
        'geometry' => array(
            'type' => 'Point',
            'coordinates' => ['$long', '$lat']
        ),
        'properties' => array(
            'title' => '$title',
            'description' => '$description',
            'image' => '$image',
            'url' => '$url',
            "marker-symbol" => "music"
        ),
    );
}

此处输出:

Array
(
    [0] => Array
        (
            [type] => Feature
            [geometry] => Array
                (
                    [type] => Point
                    [coordinates] => Array
                        (
                            [0] => $long
                            [1] => $lat
                        )

                )

            [properties] => Array
                (
                    [title] => $title
                    [description] => $description
                    [image] => $image
                    [url] => $url
                    [marker-symbol] => music
                )

        )

    [1] => Array
        (
            [type] => Feature
            [geometry] => Array
                (
                    [type] => Point
                    [coordinates] => Array
                        (
                            [0] => $long
                            [1] => $lat
                        )

                )

            [properties] => Array
                (
                    [title] => $title
                    [description] => $description
                    [image] => $image
                    [url] => $url
                    [marker-symbol] => music
                )

        )

) 

运行 下面的代码可以看到没有 [] 的 json 输出。

echo json_encode( (object) $programme_array ); 

输出:

{"0":{"type":"Feature","geometry":{"type":"Point","coordinates":["$long","$lat"]},"properties":{"title":"$title","description":"$description","image":"$image","url":"$url","marker-symbol":"music"}},"1":{"type":"Feature","geometry":{"type":"Point","coordinates":["$long","$lat"]},"properties":{"title":"$title","description":"$description","image":"$image","url":"$url","marker-symbol":"music"}}}

这是我经过多次试验和错误后得出的结论。

<?php 

$geojson = array(
    'type' => 'FeatureCollection', 
    'features' => array()
);

$programmes = $pages->find('parent=programme, sort=sort');
foreach ($programmes as $programme) {

    $marker = array(
        'type' => 'Feature',
        'properties' => array(
            'title' => $programme->title,
            'url' => $programme->url,
            'summary' => $programme->programme_summary,
            'image' => $programme->programme_venue_image->url
        ),
        'geometry' => array(
            'type' => 'Point',
            'coordinates' => array( 
                $programme->programme_location->lng,
                $programme->programme_location->lat
            )
        )
    );
    array_push($geojson['features'], $marker);

}
$programme_json = json_encode($geojson);

?>

在没有它们的 json 中获得 [] 的最简单方法是这样做:

//$json 是你的 json 没有 [] //$data 一个空数组

$数据[]=$json; print_r($数据); // 你的 $data 现在是 json with []