从 JSON 中获取平面结构中的每个名称值

Question

我有一个 JSON 文件，其中的数据结构如下：

{
    "first": {
        "second": "example",
        "third": {
            "fourth": "example2",
            "fifth": "example3"
        }
    }
}

有没有办法将其转换为平面结构以仅获取具有字符串值的名称-值对？从这个 JSON 我想得到这样的东西：

{
"second": "example",
"fourth": "example2",
"fifth": "example3"
}

Answer 1

这可能会给您一些纯粹的想法 JavaScript 如何展平您的对象。它很粗糙，但可以扩展：

function flatten(obj) {
    var flattened = {};

    for (var prop in obj)
        if (obj.hasOwnProperty(prop)) {
            //If it's an object, and not an array, then enter recursively (reduction case).
            if (typeof obj[prop] === 'object' && 
                Object.prototype.toString.call(obj[prop]) !== '[object Array]') {
                var child = flatten(obj[prop]);

                for (var p in child)
                   if (child.hasOwnProperty(p))
                       flattened[p] = child[p];
            }
            //Otherwise if it's a string, add to our flattened object (base case).
            else if (typeof obj[prop] === 'string')
                flattened[prop] = obj[prop];
        }

    return flattened;
}

fiddle

Answer 2

可以通过递归函数来完成：

var obj = {
"first": {
    "second": "example",
    "third": {
        "fourth": "example2",
        "fifth": "example3"
    }
}
};


function parseObj(_object) {
    var tmp = {};
    $.each(_object, function(k, v) {
  if(typeof v == 'object') {
    tmp = $.extend({}, tmp, parseObj(v));
  } else {
    tmp[k] = v; 
  }

});
    return tmp;
}

var objParsed = {};
objParsed = parseObj(obj);
console.log(objParsed);

这里正在运行 JSFiddle：https://jsfiddle.net/0ohbyu7b/

从 JSON 中获取平面结构中的每个名称值

Get every name-value from JSON in flat structure

javascript

json

structure