具有相同列的多个 JOIN SQL 服务器
Multiple JOINs with same column SQL Server
我必须从 GraphNodes
select id
而相同的 id
存在于 GraphEdges
的两列中,即 Source_Node
和 Target_Node
。 table的结构如下:
图形节点
+---+---------+-------------------+------------+-----------+
| id | Node_ID | Node | Node_Label | Node_Type |
+---+---------+-------------------+------------+-----------+
| 1 | 677 | Nuno Vasconcelos | Author | 1 |
| 2 | 1359 | Peng Shi | Author | 1 |
| 3 | 6242 | Z. Q. Shi | Author | 1 |
+----+---------+------------------+------------+-----------+
GraphEdges
+------------+------------------+-------------+------------------+------+-----------+
|Source_Node | Source_Node_Type | Target_Node | Target_Node_Type | Year | Edge_Type |
+------------+------------------+-------------+------------------+------+-----------+
| 1 | 1 | 10965 | 2 | 2005 | 1 |
| 1 | 1 | 10179 | 2 | 2007 | 1 |
| 1 | 1 | 10965 | 2 | 2007 | 1 |
+------------+------------------+-------------+------------------+------+-----------+
我只显示了两个 table 的 3 行,只是为了了解 table 的结构。我将查询用作:
SELECT GN.id as Node_ID,
COUNT(DISTINCT(CONCAT(GE.Source_Node, '-', GE.Target_Node)))
AS Mutual_Links -- OR Node_Degree
FROM GraphEdges GE
JOIN GraphNodes GN ON GN.id = GE.Source_Node --How to JOIN this
AND GN.id = GE.Target_Node --How to JOIN this
WHERE (Source_Node IN (SELECT id FROM GraphNodes
WHERE id BETWEEN 1 AND 510)
AND Edge_Type IN (1, 2, 3))
OR (Target_Node IN (SELECT id FROM GraphNodes
WHERE id BETWEEN 1 AND 510)
AND Edge_Type IN (1, 2, 3))
GROUP BY GN.id
我想要以下形式的输出:
+--------+-------------+
|Node_ID | Mutual_Links|
+--------+-------------+
| 1 | 31 |
| 2 | 23 |
| 3 | 12 |
| ... | ... |
+--------+-------------+
问题是如何加入 GraphEdges
和 GraphNodes
我可以获得 id
OR Node_ID
形式 GraphNodes
和 COUNT DISTINCT Mutual_Links 来自 GraphEdges
。
这样的怎么样
;with thedata ( id, MutualLinks )
as (Select id, MutualLinks = count(*) from [dbo].[GraphNodes]
inner join [dbo].[GraphEdges] on Source_node = node_id
group by id
union all
Select id, MutualLinks = count(*) from [dbo].[GraphNodes]
inner join [dbo].[GraphEdges] on target_node = node_id
group by id )
Select id, total = sum(MutualLinks)
from thedata
group by id
我必须从 GraphNodes
select id
而相同的 id
存在于 GraphEdges
的两列中,即 Source_Node
和 Target_Node
。 table的结构如下:
图形节点
+---+---------+-------------------+------------+-----------+
| id | Node_ID | Node | Node_Label | Node_Type |
+---+---------+-------------------+------------+-----------+
| 1 | 677 | Nuno Vasconcelos | Author | 1 |
| 2 | 1359 | Peng Shi | Author | 1 |
| 3 | 6242 | Z. Q. Shi | Author | 1 |
+----+---------+------------------+------------+-----------+
GraphEdges
+------------+------------------+-------------+------------------+------+-----------+
|Source_Node | Source_Node_Type | Target_Node | Target_Node_Type | Year | Edge_Type |
+------------+------------------+-------------+------------------+------+-----------+
| 1 | 1 | 10965 | 2 | 2005 | 1 |
| 1 | 1 | 10179 | 2 | 2007 | 1 |
| 1 | 1 | 10965 | 2 | 2007 | 1 |
+------------+------------------+-------------+------------------+------+-----------+
我只显示了两个 table 的 3 行,只是为了了解 table 的结构。我将查询用作:
SELECT GN.id as Node_ID,
COUNT(DISTINCT(CONCAT(GE.Source_Node, '-', GE.Target_Node)))
AS Mutual_Links -- OR Node_Degree
FROM GraphEdges GE
JOIN GraphNodes GN ON GN.id = GE.Source_Node --How to JOIN this
AND GN.id = GE.Target_Node --How to JOIN this
WHERE (Source_Node IN (SELECT id FROM GraphNodes
WHERE id BETWEEN 1 AND 510)
AND Edge_Type IN (1, 2, 3))
OR (Target_Node IN (SELECT id FROM GraphNodes
WHERE id BETWEEN 1 AND 510)
AND Edge_Type IN (1, 2, 3))
GROUP BY GN.id
我想要以下形式的输出:
+--------+-------------+
|Node_ID | Mutual_Links|
+--------+-------------+
| 1 | 31 |
| 2 | 23 |
| 3 | 12 |
| ... | ... |
+--------+-------------+
问题是如何加入 GraphEdges
和 GraphNodes
我可以获得 id
OR Node_ID
形式 GraphNodes
和 COUNT DISTINCT Mutual_Links 来自 GraphEdges
。
这样的怎么样
;with thedata ( id, MutualLinks )
as (Select id, MutualLinks = count(*) from [dbo].[GraphNodes]
inner join [dbo].[GraphEdges] on Source_node = node_id
group by id
union all
Select id, MutualLinks = count(*) from [dbo].[GraphNodes]
inner join [dbo].[GraphEdges] on target_node = node_id
group by id )
Select id, total = sum(MutualLinks)
from thedata
group by id