如何从用户输入中找到最大和最小的数字？（同时循环）

Question

老实说，我不确定从哪里开始，我能够使用用户的输入找到平均值，但似乎无法从输入的数字中找出最大或最小的数字。有什么方法可以使用吗？任何帮助都会很棒。谢谢。

编辑：有点明白了。然而，答案似乎总是最大数 = 2.1478... 或最小数 = -2.1478...

Scanner input = new Scanner(System.in);


System.out.println("Enter the number of grades: ");
double random = input.nextDouble();
double min = Integer.MIN_VALUE;
double max = Integer.MAX_VALUE;

double total=0;
int count = 1;
while (count < random+1) {




    System.out.println("Enter grade " + count + ":");

    double somenumber = input.nextDouble();
    total+=somenumber;

    count++;

    if (somenumber > max){
        max = somenumber;
    }
if (somenumber < min){
    min = somenumber;
}


}
System.out.println("Total is " + total);
System.out.println("Average is " + (total/random));
System.out.println("Largest number is " + max);
System.out.println("Smallest number is" + min);



        }

}

Answer 1

你想要一些看起来像

的代码

double min = Double.MAX_VALUE;
double max = 0.00;  // assume use positive numbers

while (count < random+1) {

System.out.println("Enter grade " + count + ":");

double somenumber = input.nextDouble();
total+=somenumber;

count++;

max = Math.max (somenumber, max);
min = Math.min (somenumber, min);

}

Answer 2

上面的 while 循环...

double max = 0;
double min = Double.MIN_VALUE;

设置一些数字后循环...

if (someNumber > max){
  max = someNumber;
}
if (someNumber < min){
  min = someNumber;
}

Np 很高兴它有所帮助 :) 您应该考虑使用 for 循环而不是 while 循环，并在循环外声明 someNumber，如下所示：

double someNumber;
for (int i = 1; i <= random; i++){
  //...
}

为了让它更干净，您可以将 for 循环中的 i <= random 替换为

i <= readNumGrades(input);
private double  readNumGrades(Scanner in){
  System.out.println("Enter the number of grades");
  return in.nextDouble();
}

因此您不再需要变量 count 和 random

Answer 3

编辑已更新为使用 Double，现在使用您的原始循环条件。

import java.util.Scanner;

public class Test {

    public static void main(String[] args) {

        Scanner input = new Scanner(System.in);
        double smallest = Double.POSITIVE_INFINITY; //Initialize to largest int possible
        double largest = Double.NEGATIVE_INFINITY; //Initialize to smallest int possible
        System.out.println("Enter the number of grades: ");
        double random = input.nextDouble();
        int count = 1;

        while (count < random + 1) {
            System.out.print("Input Number: ");
            Double x = input.nextDouble();
            if (x < smallest) {
                smallest = x;
            }
            if (x > largest) {
                largest = x;
            }
            count++;
        }
        System.out.println("Smallest: " + smallest + ", Largest: " + largest);
    }
}

样本运行：

run:
Enter the number of grades:
5
Input Number: 2.5454
Input Number: 3.454
Input Number: -100.54
Input Number: 5687
Input Number: 579873.5654
Smallest: -100.54, Largest: 579873.5654
BUILD SUCCESSFUL (total time: 15 seconds)

Answer 4

谢谢大家的指教。但是，当我运行我的程序。我无法获得最大值和最小值的正确答案。

编辑：已解决。感谢所有贡献者。 <33

Scanner input = new Scanner(System.in);


System.out.println("Enter the number of grades: ");
double random = input.nextDouble();
double min = Integer.MIN_VALUE;
double max = Integer.MAX_VALUE;

double total=0;
int count = 1;
while (count < random+1) {




    System.out.println("Enter grade " + count + ":");

    double somenumber = input.nextDouble();
    total+=somenumber;

    count++;

    if (somenumber > max){
        max = somenumber;
    }
if (somenumber < min){
    min = somenumber;
}


}
System.out.println("Total is " + total);
System.out.println("Average is " + (total/random));
System.out.println("Largest number is " + max);
System.out.println("Smallest number is" + min);



        }

}

最大的数字是 2.14748 最小的数字是 -2.147478...这就是打印出来的...我是不是算术错误了？

如何从用户输入中找到最大和最小的数字？（同时循环）

How do I find the largest number and the smallest number from the user input? (while loop)

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如何从用户输入中找到最大和最小的数字？ （同时循环）

How do I find the largest number and the smallest number from the user input? (while loop)

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max

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如何从用户输入中找到最大和最小的数字？（同时循环）