添加其他 Link header
Add additional Link header
这可能是一个愚蠢的问题,但是如何在 Nancy 的回复中添加额外的 Link
header?
我做不到
context.Response.Headers.Add("Link", "value");
因为如果已经有 header 集,那将失败。我也不能使用扩展
context.Response.WithHeader("Link", "value");
因为它会替换任何先前存在的 headers。
难道没有一种方便的方法来处理多个 headers 吗?
根据 RFC,Link Header 允许使用逗号 (",") 分隔的多个值。
Link: </TheBook/chapter2>; rel="previous"; title*=UTF-8'de'letztes%20Kapitel,
</TheBook/chapter4>; rel="next"; title*=UTF-8'de'n%c3%a4chstes%20Kapitel
所以也许您应该手动添加多个链接,然后创建 header。
String link1 = @"</TheBook/chapter2>; rel="previous"; title*=UTF-8'de'letztes%20Kapitel";
String link2 = @"</TheBook/chapter4>; rel="next"; title*=UTF-8'de'n%c3%a4chstes%20Kapitel";
String linkHeader = link1+","+link2;
context.Response.Headers.Add("Link", linkHeader);
这就是我用扩展方法做的。注意检查 Link header 是否已经存在
public static Response AsCreatedResourceWithLinks(this IResponseFormatter formatter, Resource resource)
{
return CreateResponse(formatter, resource.Id.ToString(), resource.Links);
}
private static Response CreateResponse(IResponseFormatter formatter, string id, IEnumerable<ResourceLink> links = null)
{
string url = formatter.Context.Request.Url.ToString();
var response = new Response { StatusCode = HttpStatusCode.Created, Headers = { { "Location", url + "/" + id } } };
if (links != null && links.Any())
{
foreach (var resourceLink in links)
{
var link = "<" + url + "/" + resourceLink.Link + ">; anchor=\"" + url + "/" + resourceLink.Anchor + "\"; rel=\"" + resourceLink.Rel + "\"";
if (response.Headers.ContainsKey("Link"))
{
response.Headers["Link"] += "," + link;
}
else
{
response.Headers.Add("Link", link);
}
}
}
return response;
}
Resource & ResourceLink
类 看起来像这样:
public class Resource
{
public int Id { get; set; }
public List<ResourceLink> Links { get; set; }
}
public class ResourceLink
{
public string Link { get; set; }
public string Anchor { get; set; }
public string Rel { get; set; }
}
用法是这样的:
Post["/"] = _ =>
{
//Returns Id and Links for Location/Links headers
var resource = something.SaveResource();
return Response.AsCreatedResourceWithLinks(resource);`
}
这可能是一个愚蠢的问题,但是如何在 Nancy 的回复中添加额外的 Link
header?
我做不到
context.Response.Headers.Add("Link", "value");
因为如果已经有 header 集,那将失败。我也不能使用扩展
context.Response.WithHeader("Link", "value");
因为它会替换任何先前存在的 headers。
难道没有一种方便的方法来处理多个 headers 吗?
根据 RFC,Link Header 允许使用逗号 (",") 分隔的多个值。
Link: </TheBook/chapter2>; rel="previous"; title*=UTF-8'de'letztes%20Kapitel,
</TheBook/chapter4>; rel="next"; title*=UTF-8'de'n%c3%a4chstes%20Kapitel
所以也许您应该手动添加多个链接,然后创建 header。
String link1 = @"</TheBook/chapter2>; rel="previous"; title*=UTF-8'de'letztes%20Kapitel";
String link2 = @"</TheBook/chapter4>; rel="next"; title*=UTF-8'de'n%c3%a4chstes%20Kapitel";
String linkHeader = link1+","+link2;
context.Response.Headers.Add("Link", linkHeader);
这就是我用扩展方法做的。注意检查 Link header 是否已经存在
public static Response AsCreatedResourceWithLinks(this IResponseFormatter formatter, Resource resource)
{
return CreateResponse(formatter, resource.Id.ToString(), resource.Links);
}
private static Response CreateResponse(IResponseFormatter formatter, string id, IEnumerable<ResourceLink> links = null)
{
string url = formatter.Context.Request.Url.ToString();
var response = new Response { StatusCode = HttpStatusCode.Created, Headers = { { "Location", url + "/" + id } } };
if (links != null && links.Any())
{
foreach (var resourceLink in links)
{
var link = "<" + url + "/" + resourceLink.Link + ">; anchor=\"" + url + "/" + resourceLink.Anchor + "\"; rel=\"" + resourceLink.Rel + "\"";
if (response.Headers.ContainsKey("Link"))
{
response.Headers["Link"] += "," + link;
}
else
{
response.Headers.Add("Link", link);
}
}
}
return response;
}
Resource & ResourceLink
类 看起来像这样:
public class Resource
{
public int Id { get; set; }
public List<ResourceLink> Links { get; set; }
}
public class ResourceLink
{
public string Link { get; set; }
public string Anchor { get; set; }
public string Rel { get; set; }
}
用法是这样的:
Post["/"] = _ =>
{
//Returns Id and Links for Location/Links headers
var resource = something.SaveResource();
return Response.AsCreatedResourceWithLinks(resource);`
}