查找给定用户输入的最大数和最小数（方法）

Question

我一直在尝试输入正确的代码以从用户输入中找到最大的数字和最小的数字这是我到目前为止的代码，我能够找到平均值，是否有我可以使用的运算符？ :

package labs;

import java.util.Scanner;

public class Lab7method {

public static double readNumber(Scanner input, String prompt, String errorMessage, boolean toBePositive, boolean askForInteger) {
boolean hasError = true;    // assume to have error
double number = 0;  //initialize number


while (hasError) {
        // Prompt the user to input
        System.out.print(prompt);

        // Check if it is non-numeric data
        if (!input.hasNextDouble()) {   
            // If it is, report the error
            System.out.println(errorMessage);
            input.next();   // throw the input away by reading it
        } else if (askForInteger && !input.hasNextInt()) {
            // report the non-integer error
            System.out.println(errorMessage);
            input.next();   // throw the input away by reading it
        }
        else {
            // read the number
            number = input.nextDouble();

            // if the caller wants only positive number, check for negative or zero
            if (toBePositive && number <= 0)
                System.out.println(errorMessage); // report the error
            else
                // end the error checking loop
                hasError = false;
        }
    }

    // return the number to the caller
    return number;
}

// the really used method
public static int readInteger(Scanner input, String prompt, String errorMessage) {
    // invoke the readNumber() to an integer
    int anInteger = (int)readNumber(input, prompt, errorMessage, false, true);

    // return to the caller
    return anInteger;
}


// the really used method
public static double readDouble(Scanner input, String prompt, String errorMessage) {
    // invoke the readNumber() to do the actual work
    double aNumber = readNumber(input, prompt, errorMessage, false, false);

    // return to the caller
    return aNumber;
}

// the really used read positive double method
public static double readPositiveDouble(Scanner input, String prompt, String errorMessage) {
    // invoke the readNumber() to get a positive floating point number
    double aNumber = readNumber(input, prompt, errorMessage, true, false);

    // return to the caller
    return aNumber;
}

public static int readPositiveInt(Scanner input, String prompt, String errorMessage) {
    int anposInteger = (int) readNumber(input, prompt, errorMessage, true, false);
    return anposInteger;
}

public static void main(String[] args) {
    // Create a Scanner object
    Scanner input = new Scanner(System.in);

    //initial account balance//

    int noofgrades = readPositiveInt(input, "Enter number of grades: ", "Error you did not enter a positive integer:");
    double lowestGrade = 0;
    double highestGrade = 0;    
    double sumOfGrade = 0;
    double grade = 0;



    for (int i = 0; i < noofgrades; i++){           

        double Grade = 0;   
    // monthly interest rate//

    double mograde = readPositiveDouble(input, "Please enter grade " + (i +1) + ": ", "Errorrrrrrrr");


    sumOfGrade += mograde;
    }

    double averagegrade = sumOfGrade/noofgrades;

     // Do I use these -> Double.MAX_VALUE;
     // Do I use these -> Double.MIN_VALUE;     


        System.out.printf("The average of the grades entered are: %4.2f\n"
                            + "The highest grade: %4.2f\n" + "The lowest grade is: %4.2f\n" 
                            , averagegrade, highestGrade, lowestGrade);

Answer 1

你只需要在 main 方法的 for 循环中添加几个 if 语句来找出最小值和最大值，例如：

for (int i = 0; i < noofgrades; i++) {

    double Grade = 0;
    // monthly interest rate//

    double mograde = readPositiveDouble(input, "Please enter grade " + (i + 1) + ": ", "Errorrrrrrrr");

    if (i == 0) {
        lowestGrade = mograde;
        highestGrade = mograde;
    } else {
        if (mograde < lowestGrade) {
            lowestGrade = mograde;
        }
        if (mograde > highestGrade) {
            highestGrade = mograde;
        }
    }

    sumOfGrade += mograde;
}

Answer 2

试试这个例子，输入后立即打印最小最大值：

   Scanner scanner = new Scanner(System.in);
    int n;
    int max = Integer.MIN_VALUE;
    int min = Integer.MAX_VALUE;

    while((n = scanner.nextInt()) != Integer.MIN_VALUE){
        max = n>max?n:max;
        min = n<min?n:min;
        System.out.println(String.format("Min: %d. Max %d", min, max));
    }

Answer 3

我运行它但只有最高的数字能够打印。我输入的任何输入都只打印了最小数字 0.00。

public static void main(String[] args) {
    // Create a Scanner object
    Scanner input = new Scanner(System.in);

    //initial account balance//

    int noofgrades = readPositiveInt(input, "Enter number of grades: ", "Error you did not enter a positive integer:");
    double lowestGrade = 0;
    double highestGrade = 0;    
    double sumOfGrade = 0;
    double grade = 0;



    for (int i = 0; i < noofgrades; i++){           



        double Grade = 0;   
    // monthly interest rate//

    double mograde = readPositiveDouble(input, "Please enter grade " + (i +1) + ": ", "Errorrrrrrrr");



    if(mograde < lowestGrade){
        lowestGrade = mograde;
    }


    if(mograde > highestGrade){
        highestGrade = mograde;
    }

    sumOfGrade += mograde;
    }

    double averagegrade = sumOfGrade/noofgrades;

     // Do I use these -> Double.MAX_VALUE;
     // Do I use these -> Double.MIN_VALUE;     


        System.out.printf("The average of the grades entered are: %4.2f\n"
                            + "The highest grade: %4.2f\n" + "The lowest grade is: %4.2f\n" 
                            , averagegrade, highestGrade, lowestGrade);                                                         






}

}

查找给定用户输入的最大数和最小数（方法）

Finding the largest number and smallest number given the user input (METHODS)

java

methods

max

min