MySQL SELECT 和顺序作为关联数组

MySQL SELECT and order as associative array

首先感谢您的观看,我有一个 mysql 问题,老实说我不知道​​如何解决。如果有人能帮助我,我将不胜感激。

我的 mysql 数据库中有以下两个表(请参阅下面的 link) http://www.rodneywormsbecher.com/sql-tables.jpg

我想要实现的输出如下:

array (
    [0] => category_name
        [total_userhours] => count(id) userhours
    [1] => category_name
        [total_userhours] => count(id) userhours
    [2] => category_name
        [total_userhours] => count(id) userhours
)

所以数组中的第一个结果有类别名称,在它下面,它生成一个变量来计算所有具有 userhour_category_id.

的用户小时数

提前致谢, 罗德尼

/ edit 我从回复中得到了 2 个可行的解决方案:

$data = array();
foreach ($Database->customQuery("SELECT * FROM userhour") as $r) {
    $cat_id             =   $r['userhour_category_id'];
    $cat_result_set     =   $Database->fetchSingleArray($Database->customQuery("SELECT * FROM userhour_category WHERE id={$cat_id}"));
    $cat_name           =   $cat_result_set['category_name'];
    $count              =   $Database->fetchSingleArray($Database->customQuery("SELECT COUNT(id) AS total FROM userhour WHERE userhour_category_id={$cat_id}"));
    $data[$cat_name]    =   $count['total'];
}
print_r($data);




$Sql1 = "SELECT c.category_name, count(*) AS total_userhours
          FROM `userhour` u
          JOIN `userhour_category` c
          ON (u.userhour_category_id = c.id)
          GROUP BY u.userhour_category_id";


$test = $Database->fetchAllArray($Database->customQuery($Sql1));
print_r($test);

两者都像魅力一样工作,但我更喜欢 sql 的方式。

输出:

 Array
(
    [Graphic design] => 15
    [Web design] => 9
    [Newsletter] => 1
)


Array
(
    [0] => Array
        (
            [category_name] => Web design
            [total_userhours] => 9
        )

    [1] => Array
        (
            [category_name] => Graphic design
            [total_userhours] => 15
        )

    [2] => Array
        (
            [category_name] => Newsletter
            [total_userhours] => 1
        )

)

谢谢大家

你可以这样做:

$db = mysqli_connect("host","user","pass","name");
$data = array();
foreach($db->query("select * from userhour") as $r):
    $cat = $r['project_name'];
    $data[$cat] = array(
                   'id' => $r['id'],
                   'mins' => $r['minutes_spend']
                  );
endforeach;
$db->close();

并将列更改为您需要的内容,但您应该会得到与您期望的类似的输出。

(我看不到您的 table 名称 and/or 对 userhour 事物的引用,因此请根据需要对其进行编辑。

您可以按类别将您 userhour 分组,然后对每个组进行计数:

SELECT c.category_name, count(*) AS total_userhours
FROM `userhour` u 
    JOIN `userhour_category` c 
        ON (u.userhour_category_id = c.id)
GROUP BY u.userhour_category_id

我没有测试查询,但它应该可以。