WebApi 路由 - 许多 POST 方法

WebApi routing - many POST methods

我有 WebAPI 2 应用程序。如何指定 2 个或更多 POST 方法?

我有以下 WebApiConfig:

public static void Register(HttpConfiguration config)
{
    config.SuppressDefaultHostAuthentication();
    config.Filters.Add(new HostAuthenticationFilter(OAuthDefaults.AuthenticationType));

    // Web API routes
    config.MapHttpAttributeRoutes();

    config.Routes.MapHttpRoute(
        name: "DefaultApi",
        routeTemplate: "api/{controller}/{id}",
        defaults: new { id = RouteParameter.Optional }
    );
}

和API控制器:

[RoutePrefix("api/books")]
public class BooksController : ApiController
{
    [Route("Post1")]
    [HttpPost]
    public IQueryable<string> Post1(string str)
    {
        return null;
    }

    [Route("Post2")]
    [HttpPost]
    public IQueryable<string> Post2(int id)
    {
        return null;
    }
}

我打电话都没用:

/api/books/post1

也不

/api/books/post2

为什么以及如何解决?

更新:

问题已解决,问题是简单类型作为参数。我收到 404 错误

Message=No HTTP resource was found that matches the request URI 'http://localhost:37406/api/books/post1'.

请求:

POST http://localhost:37406/api/books/post1 HTTP/1.1
User-Agent: Fiddler
Host: localhost:35979
Content-Type: application/json; charset=utf-8

{
    "str" : "Fffff"
}

和代码:

    [Route("Post1")]
    [HttpPost]
    public HttpResponseMessage Post1(string str)
    {
        return Request.CreateResponse();
    }


    [Route("Post2")]
    [HttpPost]
    public HttpResponseMessage Post2(int id)
    {
        return Request.CreateResponse();
    }

但它适用于复杂类型:

   [HttpPost]
   [Route("Post1")]
    public HttpResponseMessage Post1(Book book)
    {
        return Request.CreateResponse();
    }

    [HttpPost]
    [Route("Post2")]
    public HttpResponseMessage Post2(Book book)
    {
        return Request.CreateResponse();
    }



public class Book
{
    public int BookId { get; set; }
    public string Title { get; set; }
    public string Author { get; set; }
    public string Genre { get; set; }
}

谢谢恩科西

更新 2:

但当参数标记为 [FromBody]

时有效
    [Route("Post1")]
    [HttpPost]
    public HttpResponseMessage Post1([FromBody]string str)
    {
        return Request.CreateResponse();
    }


    [Route("Post2")]
    [HttpPost]
    public HttpResponseMessage Post2([FromBody]int id)
    {
        return Request.CreateResponse();
    }

(对于复杂类型是不必要的)。逻辑上,但是路由错误混淆了:)

摘自 Attribute Routing in ASP.NET Web API 2

HTTP Methods

Web API also selects actions based on the HTTP method of the request (GET, POST, etc). By default, Web API looks for a case-insensitive match with the start of the controller method name. For example, a controller method named PutCustomers matches an HTTP PUT request.

You can override this convention by decorating the mathod with any the following attributes:

[HttpDelete]
[HttpGet]
[HttpHead]
[HttpOptions]
[HttpPatch]
[HttpPost]
[HttpPut]

以下示例将 CreateBook 方法映射到 HTTP POST 请求。

[Route("api/books")]
[HttpPost]
public HttpResponseMessage CreateBook(Book book) { ... }

示例:

public class Book {
    public int BookId{get;set;}
    public string Title{get;set;}
    public string Author{get;set;}
    public string Genre{get;set;}
}

[RoutePrefix("api/books")]
public class BooksController : ApiController
{
    // GET api/books
    [Route("")]
    public IEnumerable<Book> Get() { ... }

    // GET api/books/5
    [Route("{id:int}")]
    public Book Get(int id) { ... }

    // POST api/books
    [HttpPost]
    [Route("")]
    public HttpResponseMessage Post1(Book book) { ... }

    // POST api/books/alternate
    [HttpPost]
    [Route("alternate")]
    public HttpResponseMessage Post2(Book book) { ... }
}

样本 POST 正文 Post1

POST http://localhost:35979/api/books HTTP/1.1
User-Agent: Fiddler
Host: localhost:35979
Content-Type: application/json; charset=utf-8
Content-Length: 80

{
    "Title":"Scary Book",
    "Author":"John Doe",
    "Genre":"Horror" 
}

样本 POST 正文 Post2

POST http://localhost:35979/api/books/alternate HTTP/1.1
User-Agent: Fiddler
Host: localhost:35979
Content-Type: application/json; charset=utf-8
Content-Length: 85

{
    "Title":"Fantastic Book",
    "Author":"Jane Doe",
    "Genre":"Fantasy" 
}