select 具有随机 ID 的不同两列

Question

我想获得每个设计和类型的不同记录，每个记录的随机 ID 无法使用

select distinct Design, Type, ID from table

它将return所有值这是我的 table

的结构

Design | Type | ID
old chair 1
old table 2
old chair 3
new chair 4
new table 5
new table 6
newest chair 7

可能的结果

Design | Type | ID
old table 2
old chair 3
new chair 4
new table 6
newest chair 7

Answer 1

如果哪一个无关紧要，您可以随时选择 maximum\minimum 个：

SELECT design,type,max(ID)
FROM YourTable
GROUP BY design,type

这不会是随机的，它总是会取 maximum\minimum 个，但这似乎并不重要。

Answer 2

试试这个：

select *
from (
select *, row_number() over (partition by Design,Type order by id desc) rowID
from @tab
) x
where rowID = 1

Answer 3

希望这对你有帮助:

WITH CTE AS
(
    SELECT Design, Type, ID, ROW_NUMBER() OVER (PARTITION BY Design, 
                                                   Type ORDER BY id DESC) rid
    FROM table
)
SELECT Design, Type, ID FROM CTE WHERE rid = 1 ORDER BY ID

select 具有随机 ID 的不同两列

select distinct two columns with random id

sql

random

db2

distinct