MySQL 创建 Tables/Views

Question

我不知道标题是否正确，但我的问题来了。因此，我想使用来自几个 tables 的数据在 phpmyadmin 中创建视图（下图），代表 lamps 维护的视图具有来自几个 tables 的字段（变电站，post_type, 区域, lamp_type, 故障与维护)

这里有 table 个连接：

我以某种方式管理并创建了类似这样的东西（下图），我设法使用这段代码创建了它：

      CREATE OR REPLACE VIEW
v_lamp_I
AS
SELECT
lamps.id,
substation.code AS sub_code,
substation.name AS sub_name,
lamps.lamp_code,
post_type.descript AS post_ty,
lamp_type.descript AS lamp_ty,
area.descript AS area_name,
rasvjeta.adress,
DATE_FORMAT(date_maintenance, "%d.%m.%Y.") AS date_main, 
lamps.geo_long,
lamps.geo_lat
FROM lamps
INNER JOIN substiation ON substiation.id = lamps.substiation_id
INNER JOIN post_type ON post_type.id = lamps.post_type_id
INNER JOIN lamp_type ON lamp_type.id = lamps.lamp_type_id
INNER JOIN area ON area.id = rasvjeta.area_id
INNER JOIN maintenance ON maintenance.lamps_id = lamps.id

我已经设法创建了视图，但问题在于该视图我只能看到维护的 rows/lamps(sifra_lampe)，只有 4 个。在 table lamps 我有 24 个条目，maintenance.But 只有 4 个条目，我想查看所有 24 个条目，如果那个特定的 lamp 没有维护，字段可以为空，日期格式为 (00-00 -00 或者它可以是 NULL) 并且对于维护的 entries/lamps 我想成为可见的日期字段。

这是 table lamp 的条目。

这里是带有维护日期的视图。如您所见，只有 6 个条目

我想查看其余条目，对于未维护的 lamps，条目可以为空或日期格式（00-00-00），对于 lamps维护的日期格式可以保持不变，简而言之，我想查看所有条目，而不仅仅是维护的条目。谢谢你，很抱歉问了这么长的问题。我不知道如何构建有意义且简短的问题，所以写下了所有内容。

Answer 1

CREATE OR REPLACE VIEW
v_lamp_I
AS
select tbl_lamp.*,DATE_FORMAT(date_maintenance, "%d.%m.%Y.") AS date_main 
from (SELECT lamps.id,
substation.code AS sub_code,
substation.name AS sub_name,
lamps.lamp_code,
post_type.descript AS post_ty,
lamp_type.descript AS lamp_ty,
area.descript AS area_name,
rasvjeta.adress,
lamps.geo_long,
lamps.geo_lat
FROM lamps
INNER JOIN substiation ON substiation.id = lamps.substiation_id
INNER JOIN post_type ON post_type.id = lamps.post_type_id
INNER JOIN lamp_type ON lamp_type.id = lamps.lamp_type_id
INNER JOIN area ON area.id = rasvjeta.area_id) as tbl_lamp
LEFT JOIN maintenance ON tbl_lamp.id = maintenance.lamps_id

Answer 2

create or replace view 
v_lamp_I as 
SELECT lamps.id,
substation.code AS sub_code,
substation.name AS sub_name,
lamps.lamp_code,
post_type.descript AS post_ty,
lamp_type.descript AS lamp_ty,
area.descript AS area_name,
rasvjeta.adress,
lamps.geo_long,
lamps.geo_lat
FROM lamps
INNER JOIN substiation ON substiation.id = lamps.substiation_id
INNER JOIN post_type ON post_type.id = lamps.post_type_id
INNER JOIN lamp_type ON lamp_type.id = lamps.lamp_type_id
INNER JOIN area ON area.id = rasvjeta.area_id;


CREATE OR REPLACE VIEW
v_lamp_new
AS
select v_lamp_I.*,DATE_FORMAT(date_maintenance, "%d.%m.%Y.") AS date_main 
from v_lamp_I
LEFT JOIN maintenance ON v_lamp_I.id = maintenance.lamps_id;

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