使用批处理文件或 powershell 取消注释 xml 节点

Question

如何使用带有 powershell 的命令提示符或简单的批处理文件取消注释 XML 文件中的节点。

<Settings> 
<SettingNode name="Installation">
<SettingNode name="Features">
      <Setting name="Features" scope="Installation">
        <StringArray>
            <!-- Uncomment the below line to activate the required features for the Pilot Version-->
            <!--<String>PilotVersion</String>-->
            <String>GlobalSearchAndReplace</String>
        </StringArray>
      </Setting>
    </SettingNode>
</SettingNode>
</Settings>

Answer 1

您可以将 xml 视为纯文本并使用替换 cmdlet :

(gc c:\files\test.xml) -replace "<!--<String>PilotVersion</String>-->","<String>PilotVersion</String>"  # |sc c:\files\test.xml if you xant to save the file

Answer 2

这是取消注释作为 XPATH 传递的 xml 元素的解决方案：

首先从 Xpath 父级获取所有注释，然后通过在 XPath 子字符串上查找匹配来识别正确的注释。

构建另一个包含该 $xml 节点但不带注释标记的节点，将 $xml 节点替换为该新节点的子节点。

有点棘手，我没有找到任何其他解决方案（纯文本不是解决方案）

# path to the file
$File = "c:\pathtoyourfile\example.xml"

# XPath to the element to un comment
$XPath = "/Settings/SettingNode[@name='Installation']/SettingNode[@name='Features']/Setting[@name='Features' and @scope='Installation']/StringArray/String"

# get xml file
$xmlFile = [xml](Get-Content $File) 

# get parent and child path from XPath
$parentXPath = $XPath.Substring(0, $XPath.LastIndexOf('/'))
$childXPath = $XPath -replace "$parentXPath/", ''

# get comment
$xmlNode = $xmlFile.SelectNodes("$parentXPath/comment()") | ? { $_.InnerText -match "<$childXPath" }

# create node containing comment content
$tempNode = $xmlFile.CreateElement("tempNode")          
$tempNode.InnerXml = $xmlNode.Value
$replaceNode = $tempNode.SelectSingleNode("/$childXPath")

# process replacement 
$xmlNode.ParentNode.ReplaceChild($replaceNode, $xmlNode)

# save change
$xmlFile.Save($File)

使用批处理文件或 powershell 取消注释 xml 节点

Uncomment xml node using batch file or powershell

xml

powershell

batch-file