LeadComponent() 在 getname() 方法中给出问题

Question

如果我设置 leadcomponent 方法，所有 btns returns 同名但我为每个按钮设置不同的名称。如果我注释掉 leadcomponent 行，它工作正常。可能发生了什么？我为所有按钮设置名称，以便我可以应用动作侦听器并根据返回的名称打开不同的表单。

我的代码：

BorderLayout gl1 = new BorderLayout();
Container middleContainer = new Container(gl1);
parentContiner.addComponent(middleContainer);
GridLayout gl2 = new GridLayout(counter / 3 + 1, 3);
gl2.setAutoFit(true);
Container gridContainer = new Container(gl2);
parentContiner.addComponent(gridContainer);

for (HashMap<String, Object> entry : homeStorage) {
  if (!"".equals(entry.get("img").toString())) {
    counter++;
    Button homeButton = new Button();
    id = entry.get("id").toString();

    imageUrl = entry.get("img").toString();
    title = entry.get("name").toString();
    homePlaceholder = homePlaceholder.scaled(screenWidth / 3 - 17, screenWidth / 3 - 17);
    encodedHomePlaceholder = EncodedImage.createFromImage(homePlaceholder, true);
    Image btnIcon = URLImage.createToStorage(encodedHomePlaceholder, "home_" + title + imageUrl, allUrl.globalHomeImageUrl + imageUrl, URLImage.RESIZE_SCALE_TO_FILL);

    homeButton.setIcon(btnIcon);
***//set the name of button to id***    
    homeButton.setName(id);

    TextArea buttonTitle = new TextArea(properCase(title));

    buttonTitle.setEditable(false);
    buttonTitle.setGrowByContent(true);
    buttonTitle.setGrowLimit(2);
    buttonTitle.setScrollVisible(false);
    Container containerBtnTitle = new Container(new FlowLayout(Label.RIGHT, Label.BOTTOM));
    containerBtnTitle.add(buttonTitle);
    gridContainer.add(LayeredLayout.encloseIn(homeButton, containerBtnTitle));
**//if i remove this line(setLeadcomponent) it works (ie returns different name as set above, otherwise all the button returns the same name (ie last id)**
    gridContainer.setLeadComponent(homeButton);
    gridContainer.revalidate();
}
    homeButton.addActionListener((e) -> {
    if (homeButton.getName().equals("3")) {
        showForm("YoutubeVideos", null);
    } else if (homeButton.getName().equals("17")) {
        showForm("k2Gallery", null);
    } else if (homeButton.getName().equals("15")) {
        showForm("EmergencyCategory", null);
    } else if (homeButton.getName().equals("2")) {
        showForm("PartyClicks", null);
    } else if (homeButton.getName().equals("1")) {
        showForm("WhereTheParty", null);
    } else if (homeButton.getName().equals("5")) {
        showForm("CocktailRecipies", null);
    }

});
}

Answer 1

每个容器只能有 1 个主要成分。您正在创建几个 homeButton，但您有 1 个 gridContainer。

LeadComponent() 在 getname() 方法中给出问题

LeadComponent() gives issues in getname() method

java

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