Post UIImage 到 Instagram 使用 Swift 类似于 SLComposeViewController

Question

我有一个 iOS Xcode 7 Swift 2 我正在做的项目。该应用使用以下方式将照片发布到 Facebook 和 Twitter：

var shareToFacebook: SLComposeViewController = SLComposeViewController(forServiceType: SLServiceTypeFacebook)

和

var shareToTwitter: SLComposeViewController = SLComposeViewController(forServiceType: SLServiceTypeTwitter)

喜欢将照片发布到这两个社交媒体是多么容易和简单。我不需要也不想要它们的 API。

我想为 Instagram 做一些类似且简单的事情。无需处理 Instagram API 即可执行此操作的最佳方法是什么？还是我别无选择？

我的照片 data 是使用 NSCoding 保存的，而不是 DocumentDirectory。我查看了 here 的集成，但这是针对应用 directory 中保存的照片。

就像我已经拥有的 Facebook 和 Twitter 一样简单。

Answer 1

我看了 here 并找到了解决方案：

我创建了一个 NSObject:

import UIKit
import Foundation

class InstagramManager: NSObject, UIDocumentInteractionControllerDelegate {

    private let kInstagramURL = "instagram://app"
    private let kUTI = "com.instagram.exclusivegram"
    private let kfileNameExtension = "instagram.igo"
    private let kAlertViewTitle = "Error"
    private let kAlertViewMessage = "Please install the Instagram application"

    var documentInteractionController = UIDocumentInteractionController()

    // singleton manager
    class var sharedManager: InstagramManager {
        struct Singleton {
            static let instance = InstagramManager()
        }
        return Singleton.instance
    }

    func postImageToInstagramWithCaption(imageInstagram: UIImage, instagramCaption: String, view: UIView) {
        // called to post image with caption to the instagram application

        let instagramURL = NSURL(string: kInstagramURL)
        if UIApplication.sharedApplication().canOpenURL(instagramURL!) {
            let jpgPath = (NSTemporaryDirectory() as NSString).stringByAppendingPathComponent(kfileNameExtension)
            UIImageJPEGRepresentation(imageInstagram, 1.0)!.writeToFile(jpgPath, atomically: true)
            let rect = CGRectMake(0,0,612,612)
            let fileURL = NSURL.fileURLWithPath(jpgPath)
            documentInteractionController.URL = fileURL
            documentInteractionController.delegate = self
            documentInteractionController.UTI = kUTI

            // adding caption for the image
            documentInteractionController.annotation = ["InstagramCaption": instagramCaption]
            documentInteractionController.presentOpenInMenuFromRect(rect, inView: view, animated: true)
        } else {

            // alert displayed when the instagram application is not available in the device
            UIAlertView(title: kAlertViewTitle, message: kAlertViewMessage, delegate:nil, cancelButtonTitle:"Ok").show()
        }
    }

}

然后在我的@IBAction中我使用了：

let image = self.photoImageView.image
InstagramManager.sharedManager.postImageToInstagramWithCaption(image!, instagramCaption: "\(self.description)", view: self.view)

这将打开带有 'open-in' 样式的菜单，用户可以在 Instagram（如果已安装）中打开该应用程序。

Answer 2

更新 Swift 3

import UIKit
import Foundation

class InstagramManager: NSObject, UIDocumentInteractionControllerDelegate {

    private let kInstagramURL = "instagram://app"
    private let kUTI = "com.instagram.exclusivegram"
    private let kfileNameExtension = "instagram.igo"
    private let kAlertViewTitle = "Error"
    private let kAlertViewMessage = "Please install the Instagram application"

    var documentInteractionController = UIDocumentInteractionController()

    // singleton manager
    class var sharedManager: InstagramManager {
        struct Singleton {
            static let instance = InstagramManager()
        }
        return Singleton.instance
    }

    func postImageToInstagramWithCaption(imageInstagram: UIImage, instagramCaption: String, view: UIView) {
        // called to post image with caption to the instagram application

        let instagramURL = NSURL(string: kInstagramURL)

        if UIApplication.shared.canOpenURL(instagramURL! as URL) {

            let jpgPath = (NSTemporaryDirectory() as NSString).appendingPathComponent(kfileNameExtension)

            do {
                try UIImageJPEGRepresentation(imageInstagram, 1.0)?.write(to: URL(fileURLWithPath: jpgPath), options: .atomic)

            } catch {

                print(error)
            }

            let rect = CGRect(x: 0, y: 0, width: 612, height: 612)
            let fileURL = NSURL.fileURL(withPath: jpgPath)
            documentInteractionController.url = fileURL
            documentInteractionController.delegate = self
            documentInteractionController.uti = kUTI

            // adding caption for the image
            documentInteractionController.annotation = ["InstagramCaption": instagramCaption]
            documentInteractionController.presentOpenInMenu(from: rect, in: view, animated: true)
        } else {

            /// display some message about how it didn't work
            /// Like: UIAlertController(title: kAlertViewTitle, message: kAlertViewMessage, preferredStyle: .alert)
        }
    }
}

然后在 ViewController 你想调用它...

InstagramManager.sharedManager.postImageToInstagramWithCaption(imageInstagram: <YOUR IMAGE>, instagramCaption: shareText, view: self.view)

如果安装了 Instagram，这将打开 'open-in' 功能

Answer 3

这是一个可重复使用的 class 和 swift 4+。在 Xcode 10.1.

工作

创建 swift 个空文件。

将以下代码复制并粘贴到文件中。

import UIKit
import Foundation

class InstagramHelper: NSObject, UIDocumentInteractionControllerDelegate {

    private let kInstagramURL = "instagram://den3079"
    private let kUTI = "com.instagram.exclusivegram"
    private let kfileNameExtension = "instagram.igo"
    private let kAlertViewTitle = "Error"
    private let kAlertViewMessage = "Please install the Instagram application"

    var documentInteractionController = UIDocumentInteractionController()

    // singleton manager
    class var sharedManager: InstagramHelper {
        struct Singleton {
            static let instance = InstagramHelper()
        }
        return Singleton.instance
    }


    func postImageToInstagramWithCaption(imageInstagram: UIImage, instagramCaption: String, controller: UIViewController) {
        // called to post image with caption to the instagram application

        let instagramURL = URL(string: kInstagramURL)

        DispatchQueue.main.async {

            if UIApplication.shared.canOpenURL(instagramURL!) {

                let jpgPath = (NSTemporaryDirectory() as NSString).appendingPathComponent(self.kfileNameExtension)
                if let jpegData = UIImageJPEGRepresentation(imageInstagram, 1.0) {
                    do {
                        try jpegData.write(to: URL(fileURLWithPath: jpgPath), options: .atomicWrite)

                    } catch {
                        print("write image failed")
                    }
                }else {
                    let jpegData = UIImagePNGRepresentation(imageInstagram)
                    do {
                        try jpegData?.write(to: URL(fileURLWithPath: jpgPath), options: .atomicWrite)

                    } catch {
                        print("write image failed")
                    }
                }
                let fileURL = NSURL.fileURL(withPath: jpgPath)
                self.documentInteractionController.url = fileURL
                self.documentInteractionController.delegate = self
                self.documentInteractionController.uti = self.kUTI

                // adding caption for the image
                self.documentInteractionController.annotation = ["InstagramCaption": instagramCaption]
                self.documentInteractionController.presentOpenInMenu(from: controller.view.frame, in: controller.view, animated: true)

            } else {

                // alert displayed when the instagram application is not available in the device
                self.showAlert("", message: self.kAlertViewMessage, controller: controller)
            }
        }
    }
 func showAlert(_ title: String, message: String, controller : UIViewController){

    let alert = UIAlertController(title: title, message: message, preferredStyle: UIAlertControllerStyle.alert)
    let okAction = UIAlertAction(title: "OK", style: UIAlertActionStyle.default, handler: { action -> Void in
        //Just dismiss the action sheet
        let selector: Selector = NSSelectorFromString("alertOkButtonHandler")
        if controller.responds(to: selector){
            _ = controller.perform(selector)
        }
    })
    alert.addAction(okAction)
    controller.present(alert, animated: true, completion: nil)
}}

并在 ViewController class.

中使用此功能

InstagramHelper.sharedManager.postImageToInstagramWithCaption(imageInstagram: img!, instagramCaption: "www.google.com", controller: self)

Post UIImage 到 Instagram 使用 Swift 类似于 SLComposeViewController

Post UIImage to Instagram using Swift similar to SLComposeViewController

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