python 如何模拟一个方法?

python how to mock a method?

我想测试一个httppost方法,这个方法会调用一些服务,但是这个服务不能在本地测试机上运行,​​所以我想模拟它。

test.py:

@route(bp, '/count', methods=['POST'])
def count():
   from module import service
   ...
   total, ids = service(id, page, count) // total is a integer, ids is a list.
   ...
   return {'total': total, 'ids': ids}

测试用例:

@mock.patch("module.service")
def test_search_user(self, mock_service):
    mock_service.return_value=(1, [])

    url = url_for('users.count')
    params = { .... }

    response = self._test_app.post_json(
        url, params, headers=self.request_headers, expect_errors=True)

    self.assertEqual(response.status_code, 200)

但是测试用例总是失败,它试图调用service方法,但它不能在我的机器上运行。我只是想嘲笑它,但不起作用。

任何人都可以帮助我!提前致谢!

根据@syntonym的回答,我的测试用例应该这样写:

@mock.patch("test.service")
def test_search_user(self, mock_service):
    mock_service.return_value=(1, [])

@mock.patch 实际上采用查找名称 - 而不是您要修补的对象实际所在的位置。 The documentation reads:

patch() works by (temporarily) changing the object that a name points to with another one. [...] The basic principle is that you patch where an object is looked up, which is not necessarily the same place as where it is defined.