无法在 PHP 客户端中获得 aws lambda 函数响应

Cannot get aws lambda function response in PHP client

我正尝试按照文档中的说明使用 PHP 调用一个简单的 Aws Lambda 函数,但我没有得到所需的响应。

PHP Lambda 客户端

require './aws/aws-autoloader.php';
use Aws\Lambda\LambdaClient;

$client = LambdaClient::factory(array(
            'version' => "latest",
            'credentials' => array(
                'key' => '*******',
                'secret' => '*******'
            ),
            'region' => '*******'
        ));

$response = $client->invoke([
    'FunctionName' => 'myLambda', // REQUIRED
    'InvocationType' => 'RequestResponse',
    'Payload' => '{"key":"value"}',
        ]);

echo "<pre>";
print_r($response);
print_r($response->data);

?>

Node.js Lambda 函数 这只有 returns "success" 成功执行 Lambda 函数的简单代码。它在 Amazon Lambda 控制台中的工作发现。

exports.handler = function(event, context){

    context.succeed("success");
};

亚马逊的回应 我得到一个我无法访问的私有数据对象。根据文档,有效负载应该是函数的响应。但是,我得到一个对象,我又不能访问它,因为父对象数据是私有的。

Aws\Result Object
(
    [data:Aws\Result:private] => Array
        (
            [Payload] => GuzzleHttp\Psr7\Stream Object
                (
                    [stream:GuzzleHttp\Psr7\Stream:private] => Resource id #6
                    [size:GuzzleHttp\Psr7\Stream:private] => 
                    [seekable:GuzzleHttp\Psr7\Stream:private] => 1
                    [readable:GuzzleHttp\Psr7\Stream:private] => 1
                    [writable:GuzzleHttp\Psr7\Stream:private] => 1
                    [uri:GuzzleHttp\Psr7\Stream:private] => php://temp
                    [customMetadata:GuzzleHttp\Psr7\Stream:private] => Array
                        (
                        )

                )

            [StatusCode] => 200
            [FunctionError] => 
            [LogResult] => 
            [@metadata] => Array
                (
                    [statusCode] => 200
                    [effectiveUri] => https://lambda.*********.amazonaws.com/2015-03-31/functions/myLambda/invocations
                    [headers] => Array
                        (
                            [content-type] => application/json
                            [date] => Wed, 06 Apr 2016 12:33:05 GMT
                            [x-amzn-remapped-content-length] => 0
                            [x-amzn-requestid] => ******-*****-*****-****-*******************
                            [content-length] => 9
                            [connection] => keep-alive
                        )

                    [transferStats] => Array
                        (
                            [http] => Array
                                (
                                    [0] => Array
                                        (
                                        )

                                )

                        )

                )

        )

)

那么,如何从 Lambda 函数访问响应?这可能是什么问题?

更新

我可以使用 print_r($response['Payload']); 访问有效载荷 但是,仍然没有用,因为 Payload 没有按预期到达。

哦!好吧,我找到了答案。 您需要调用 Payload.

GuzzleHttp\Psr7\Stream 对象的 __toString() 方法

所以,执行 print_r($response['Payload']->__toString()); 输出 "Success",这是 Lambda 函数的期望响应,也是我正在寻找的响应。

希望这对以后的人有所帮助。

另一种方法是调用 getContents() 流对象,如下所示:

$result = $client->invoke(array(
          // FunctionName is required
          'FunctionName' => 'myService-beta-hello',
          'InvocationType' => 'RequestResponse',
            'LogType' => 'Tail',
            'Payload' => '{"key1":"value1", "key2":"value2","key3":"value3"}',
            //'Qualifier' => 'string',
                ));
print "<pre>";
print_r($result);
print_r($result['Payload']->getContents());
print "</pre>";
require_once 'aws/aws-autoloader.php';
use Aws\Lambda\LambdaClient;
$client = LambdaClient::factory([
    'version' => 'latest',
    'region'  => 'us-east-1',
    'credentials' => [
        'key'    => 'YOUR_AWS_ACCESS_KEY_ID',
        'secret' => 'YOUR_AWS_SECRET_ACCESS_KEY',
     ]
]);

$result = $client->invoke([
    // The name your created Lamda function
    'FunctionName' => 'calculation',
]);

var_dump((string)$result->get('Payload'));