两个客户端不能在套接字客户端-服务器连接中相互交谈

Question

当一个客户端发送输入时，在第二个客户端中它不会打印消息（即未收到消息）。当第二个客户端发送输入时，在第一个客户端中它不会打印消息（即未收到消息）。

我了解到 client.send(message) 在服务器脚本中，它会将消息发送给连接到服务器的所有客户端，因此您无需指定发送给谁。

客户

import socket
import threading

class sendThread(threading.Thread):
    def __init__(self, ip, port, client):
        threading.Thread.__init__(self)
        self.port = port
        self.ip = ip
        self.client = client
        print "[+] New send thread started for "+ip+":"+str(port) + "...Everything went successful!"

    def run(self):
        while True:
            data = raw_input("Enter command:")
            self.client.send(data)

class receiveThread(threading.Thread):
    def __init__(self, ip, port, client):
        threading.Thread.__init__(self)
        self.ip = ip
        self.port = port
        self.client = client
        print "[+] New receive thread started for "+ip+":"+str(port) + "...Everything went successful!"

    def run(self):
        print "Entered run method"
        size = 1024
        while True:
            data = self.client.recv(size)
            if data != "" or data:
                print data


def client():
    port = 1724
    ip = '127.0.0.1'
    print "Connection from : "+ip+":"+str(port)
    client = socket.socket()
    client.connect((ip, port))
    receive = receiveThread(ip, port, client)
    print "b1"
    receive.start()
    print "b2"
    send = sendThread(ip, port, client)
    print "b3"
    send.start()
    while send.isAlive() and receive.isAlive():
        continue
    print "-----END of While TRUE------"
    print "Client disconnected..."

client()

服务器

import socket
import threading

global num
num = 0

class serverThread(threading.Thread):
    def __init__(self, client, address):
        global num
        num = num + 1
        self.id = num
        threading.Thread.__init__(self)
        self.client = client
        self.address = address
        print "serverThread init finished-" + str(self.id)

    def run(self):
        print "r1 num-" + str(self.id)
        size = 1024
        while True:
                print "r2-" + str(self.id)
                data = self.client.recv(size)
                print "r3..... " + data
                print "r4-" + str(self.id)
                if data:
                    print "r5-" + str(self.id)
                    response = data

                    self.client.send(response)
                    print "r6-" + str(self.id)
                else:
                    print "r7-" + str(self.id)
                    raise Exception('Client disconnected-' + str(self.id) )

def create(ipHost, port):
    server = socket.socket()
    server.bind((ipHost, port))
    print "The server was created successfully."
    return server

def listen(server):
    server.listen(5)
    client, address = server.accept()
    c1 = serverThread(client, address)
    c1.start()
    client, address = server.accept()
    c2 = serverThread(client, address)
    c2.start()
    print "finished both threads created"

    while c1.isAlive() and c2.isAlive():
        continue

server = create("0.0.0.0", 1724)
listen(server)

两个客户端都有以下输出：

Connection from : 127.0.0.1:1720
[+] New receive thread started for 127.0.0.1:1720...Everything went successful!
b1
Entered run method
b2
[+] New send thread started for 127.0.0.1:1720...Everything went successful!
b3
Enter command:Hello
Enter command:Hello

当两个客户端发送相同的消息时就是这种情况（因此它们的输出中都会有 Enter command:Hello。

如果客户端 1 发送 "Hello" 并且客户端 2 发送 "Hi": 客户端 1 将作为输出Hello 和客户端 2 将具有输出 Hi，而不是在输出 Hi 和 Hello.

中同时接收和打印

注意：如果您指出我的错误，而不是给我一个新版本，将不胜感激。

Answer 1

你的错误是，你只将文本从客户端发送回同一个客户端：

self.client.send(response)

即客户端c1和客户端c2是独立的，互不认识。

两个客户端不能在套接字客户端-服务器连接中相互交谈

Two clients can't talk to each other in a socket client-server connection

python

sockets

multithreading

client-server

output

客户

服务器