为什么 .then() 在 promise 实际解决之前被解雇?
Why is .then() fired before promise has actually resolved?
我正在尝试 return 来自异步任务的承诺,以便我可以使用 .then() 调用使它们同步。不幸的是,我遇到了一些非常奇怪的行为。基本上,第三个 then() 在第二个解析之前执行。有人可以解释发生了什么吗?这是我的代码:
function runReleaseLoop() {
console.log('Starting release loop');
const themes = ['blue', 'red'];
return new Promise(resolve => {
buildReleases(themes, resolve);
})
}
function buildReleases(themes, onComplete) {
console.log(themes);
if (themes.length === 0) {
onComplete();
} else {
const theme = themes.pop();
Promise.resolve()
.then(setTheme(theme))
.then(someDelayedTask(theme))
.then(buildReleases(themes, onComplete));
}
}
function setTheme(theme) {
return new Promise(resolve => {
console.log(`Setting theme to ${theme}`);
resolve();
});
}
function someDelayedTask(theme) {
console.log(`Starting delayed task related to ${theme}`);
return new Promise(resolve => {
setTimeout(() => {
console.log(`Finished delayed task related to ${theme}`);
resolve();
}, 3000)
});
}
// Run the process
runReleaseLoop()
.then(() => {
console.log('Release loop finished')
});
这是我的控制台输出:
"Starting release loop"
["blue", "red"]
"Setting theme to red"
"Starting delayed task related to red"
["blue"]
"Setting theme to blue"
"Starting delayed task related to blue"
[]
"Release loop finished"
"Finished delayed task related to red"
"Finished delayed task related to blue"
您正在同步调用这些函数中的每一个(setTheme
、someDelayedTask
和 buildReleases
),然后将它们的 return 值(承诺)传递给 then
而不是将函数本身传递给 then:
Promise.resolve()
.then(setTheme(theme))
.then(someDelayedTask(theme))
.then(buildReleases(themes, onComplete));
这是一种解决方案:
Promise.resolve()
.then(_ => setTheme(theme))
.then(_ => someDelayedTask(theme))
.then(_ => buildReleases(themes, onComplete));
这是经过上述更改后的代码输出:
Starting release loop
[ 'blue', 'red' ]
Setting theme to red
Starting delayed task related to red
Finished delayed task related to red
[ 'blue' ]
Setting theme to blue
Starting delayed task related to blue
Finished delayed task related to blue
[]
Release loop finished
第一个问题是,您将承诺与回调混合在一起。第二种是一次性调用所有函数 setTheme, someDelayedTask, buildReleases
:
function runReleaseLoop() {
console.log('Starting release loop');
const themes = ['blue', 'red'];
return buildReleases(themes);
}
function buildReleases(themes) {
console.log(themes);
if (themes.length === 0) {
return Promise.resolve();
}
const theme = themes.pop();
return setTheme(theme)
.then(() => someDelayedTask(theme))
.then(() => buildReleases(themes));
}
function setTheme(theme) {
console.log(`Setting theme to ${theme}`);
}
function someDelayedTask(theme) {
console.log(`Starting delayed task related to ${theme}`);
return new Promise(resolve => {
setTimeout(() => {
console.log(`Finished delayed task related to ${theme}`);
resolve();
}, 3000)
});
}
// Run the process
runReleaseLoop()
.then(() => console.log('Release loop finished'));
我正在尝试 return 来自异步任务的承诺,以便我可以使用 .then() 调用使它们同步。不幸的是,我遇到了一些非常奇怪的行为。基本上,第三个 then() 在第二个解析之前执行。有人可以解释发生了什么吗?这是我的代码:
function runReleaseLoop() {
console.log('Starting release loop');
const themes = ['blue', 'red'];
return new Promise(resolve => {
buildReleases(themes, resolve);
})
}
function buildReleases(themes, onComplete) {
console.log(themes);
if (themes.length === 0) {
onComplete();
} else {
const theme = themes.pop();
Promise.resolve()
.then(setTheme(theme))
.then(someDelayedTask(theme))
.then(buildReleases(themes, onComplete));
}
}
function setTheme(theme) {
return new Promise(resolve => {
console.log(`Setting theme to ${theme}`);
resolve();
});
}
function someDelayedTask(theme) {
console.log(`Starting delayed task related to ${theme}`);
return new Promise(resolve => {
setTimeout(() => {
console.log(`Finished delayed task related to ${theme}`);
resolve();
}, 3000)
});
}
// Run the process
runReleaseLoop()
.then(() => {
console.log('Release loop finished')
});
这是我的控制台输出:
"Starting release loop"
["blue", "red"]
"Setting theme to red"
"Starting delayed task related to red"
["blue"]
"Setting theme to blue"
"Starting delayed task related to blue"
[]
"Release loop finished"
"Finished delayed task related to red"
"Finished delayed task related to blue"
您正在同步调用这些函数中的每一个(setTheme
、someDelayedTask
和 buildReleases
),然后将它们的 return 值(承诺)传递给 then
而不是将函数本身传递给 then:
Promise.resolve()
.then(setTheme(theme))
.then(someDelayedTask(theme))
.then(buildReleases(themes, onComplete));
这是一种解决方案:
Promise.resolve()
.then(_ => setTheme(theme))
.then(_ => someDelayedTask(theme))
.then(_ => buildReleases(themes, onComplete));
这是经过上述更改后的代码输出:
Starting release loop
[ 'blue', 'red' ]
Setting theme to red
Starting delayed task related to red
Finished delayed task related to red
[ 'blue' ]
Setting theme to blue
Starting delayed task related to blue
Finished delayed task related to blue
[]
Release loop finished
第一个问题是,您将承诺与回调混合在一起。第二种是一次性调用所有函数 setTheme, someDelayedTask, buildReleases
:
function runReleaseLoop() {
console.log('Starting release loop');
const themes = ['blue', 'red'];
return buildReleases(themes);
}
function buildReleases(themes) {
console.log(themes);
if (themes.length === 0) {
return Promise.resolve();
}
const theme = themes.pop();
return setTheme(theme)
.then(() => someDelayedTask(theme))
.then(() => buildReleases(themes));
}
function setTheme(theme) {
console.log(`Setting theme to ${theme}`);
}
function someDelayedTask(theme) {
console.log(`Starting delayed task related to ${theme}`);
return new Promise(resolve => {
setTimeout(() => {
console.log(`Finished delayed task related to ${theme}`);
resolve();
}, 3000)
});
}
// Run the process
runReleaseLoop()
.then(() => console.log('Release loop finished'));